So let's see here...
6:00 A.M. temperature is 33°F.
12:00 P.M temperature increased by 10°F making it 43°F.
3:00 P.M. temperature increased by another 12°F making it 55°F.
At 10:00 P.M it would decrease by 15°F making it 40°F.
The temperature would need to fall (or decrease) by 7°F to reach the original temperature of 33°F
Hope this helped!
X^2 - x = 7
(x - 0.5)^2 - 0.25 = 7
(x - 0.5)^2 = 7.25
(x - 0.5) = +/- sqrt 7.25
x = 0.5 +/- sqrt7.25
solution set is {-2.19, 3.19,}
1cm *10 = 10km
40cm * 10 = 400 km
50km/50 = 1cm
400km/50 = 8cm
A: 8cm
Answer:
y = 3/5 or y = -1/2
v = 0 oe v = -4/3
Step-by-step explanation:
Zero product property states that if ab = 0, then a = 0 or b = 0.
(5y - 3) (2y + 1) = 0
5y - 3 = 0 or 2y + 1 = 0
y = 3/5 or y = -1/2
2v(3v + 4) = 0
2v = 0 or 3v + 4 = 0
v = 0 oe v = -4/3
