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seraphim [82]
2 years ago
7

A pair of dice is rolled. What is the probability of getting a sum of 6?

Mathematics
1 answer:
emmasim [6.3K]2 years ago
8 0

Answer:

1/6

Step-by-step explanation:

Since you are rolling the die only one time there is only one way of you getting a 6 and that is rolling an actual 6. There are six sides to the die so you take the one 6 out of the the others and there is your probability.

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Solve.
Oduvanchick [21]

Answer:

Step-by-step explanation:

There are several approach to solving a quadratic equation; factorization, completing the square, the use of 'the almighty formula etc. Though i didn't see the steps you followed in solving, but from your answer, it is obvious you made good attempt but something is missing, your answer should be (5+√57)/2 or (5-√57)/2

5 0
3 years ago
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The camp will pay you $48.23 each day for 8 weeks. If you work 5 days each wee , how much money will you make this summer ?
AlekseyPX

Answer:$1,929.20

Step-by-step explanation:First off, I noted that the answers are pretty far apart so I rounded up to $50 to make it simpler (you should only do this if the answers are pretty far apart from one another.)

$50 per day × 5 days per week × 8 weeks = $2,000. Closest answr (because I rounded) is $1,929.20.

3 0
3 years ago
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Find the area of the region that lies inside the first curve and outside the second curve.
marishachu [46]

Answer:

Step-by-step explanation:

From the given information:

r = 10 cos( θ)

r = 5

We are to find the  the area of the region that lies inside the first curve and outside the second curve.

The first thing we need to do is to determine the intersection of the points in these two curves.

To do that :

let equate the two parameters together

So;

10 cos( θ) = 5

cos( θ) = \dfrac{1}{2}

\theta = -\dfrac{\pi}{3}, \ \  \dfrac{\pi}{3}

Now, the area of the  region that lies inside the first curve and outside the second curve can be determined by finding the integral . i.e

A = \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} (10 \ cos \  \theta)^2 d \theta - \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \  5^2 d \theta

A = \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} 100 \ cos^2 \  \theta  d \theta - \dfrac{25}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \   d \theta

A = 50 \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \begin {pmatrix}  \dfrac{cos \ 2 \theta +1}{2}  \end {pmatrix} \ \ d \theta - \dfrac{25}{2}  \begin {bmatrix} \theta   \end {bmatrix}^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}}

A =\dfrac{ 50}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \begin {pmatrix}  {cos \ 2 \theta +1}  \end {pmatrix} \ \    d \theta - \dfrac{25}{2}  \begin {bmatrix}  \dfrac{\pi}{3} - (- \dfrac{\pi}{3} )\end {bmatrix}

A =25  \begin {bmatrix}  \dfrac{sin2 \theta }{2} + \theta \end {bmatrix}^{\dfrac{\pi}{3}}_{\dfrac{\pi}{3}}    \ \ - \dfrac{25}{2}  \begin {bmatrix}  \dfrac{2 \pi}{3} \end {bmatrix}

A =25  \begin {bmatrix}  \dfrac{sin (\dfrac{2 \pi}{3} )}{2}+\dfrac{\pi}{3} - \dfrac{ sin (\dfrac{-2\pi}{3}) }{2}-(-\dfrac{\pi}{3})  \end {bmatrix} - \dfrac{25 \pi}{3}

A = 25 \begin{bmatrix}   \dfrac{\dfrac{\sqrt{3}}{2} }{2} +\dfrac{\pi}{3} + \dfrac{\dfrac{\sqrt{3}}{2} }{2} +   \dfrac{\pi}{3}  \end {bmatrix}- \dfrac{ 25 \pi}{3}

A = 25 \begin{bmatrix}   \dfrac{\sqrt{3}}{2 } +\dfrac{2 \pi}{3}   \end {bmatrix}- \dfrac{ 25 \pi}{3}

A =    \dfrac{25 \sqrt{3}}{2 } +\dfrac{25 \pi}{3}

The diagrammatic expression showing the area of the region that lies inside the first curve and outside the second curve can be seen in the attached file below.

Download docx
7 0
2 years ago
if you can travel 156 miles on 4 gallons of gasoline how many miles can you travel on 6 gallons of gas
Luden [163]
Its 234!!!!!!!!!!!!!! Just checked my work
3 0
3 years ago
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How many dimensions does a point in space have
Andreas93 [3]

Hello, hope you are having a wonderful day.

A point has 0 dimensions. It has no length, width, or depth.

So any point in space has 0 dimensions.

Now, a line has 1 dimension.

Rectangles, squares and other shapes have 2 dimensions.

Cylinders, cubes, cones and other figures have 3 dimensions.

Hope it helps. Please mark Brainliest; I really need it.

~An emotional teen who helps others with joy

Good luck.

8 0
2 years ago
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