Answer:
5
Step-by-step explanation:
Answer:
At 43.2°.
Step-by-step explanation:
To find the angle we need to use the following equation:

Where:
d: is the separation of the grating
m: is the order of the maximum
λ: is the wavelength
θ: is the angle
At the first-order maximum (m=1) at 20.0 degrees we have:

Now, to produce a second-order maximum (m=2) the angle must be:


Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.
I hope it helps you!
Answer:
n= 1/2 (
) or (0.5)
AND
n= -3/2 (
) or (-1.5)
Step-by-step explanation:
4n^2+4n=3
step1: move 3 to the other side and make the equation equal to zero.
4n^2+4n-3=0
step2: factorise the equation.
(2n-1)(2n+3)=0
step3: make each bracket equal to zero.
2n-1=0
2n+3=0
step4: solve for n values.
<u>1.</u> 2n-1=0
(add 1 for both sides)
2n=1
(divide by 2 for both sides)
n= 1/2 (
) or (0.5)
<u>2.</u> 2n+3=0
( subtract 3 for both sides)
2n=-3
(divide by 2 for both sides)
n= -3/2 (
) or (-1.5)
A parabola with an equation, y2 = 4ax has its vertex at the origin and opens to the right.
It's not just the '4' that is important, it's '4a' that matters.
This type of parabola has a directrix at x = -a, and a focus at (a, 0). By writing the equation as it is, the position of the directrix and focus are readily identifiable.
For example, y2 = 2.4x doesn't say a great deal. Re-writing the equation of the parabola as y2 = 4*(0.6)x tells us immediately that the directrix is at x = -0.6 and the focus is at (0.6, 0)