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prohojiy [21]
4 years ago
8

What is the correct factorization of x^6-y^6

Mathematics
1 answer:
Soloha48 [4]4 years ago
3 0
(x^3 - y^3)(x^3 + y^3)

You can get this by factoring based on the a^2 - b^2 model 
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If Tom, George and Mario work together, they can paint a 600 ft2 room in 4 hours. When only George and Mario work together, it t
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We call:

T = Tom's paiting rate ( \frac{ ft^{2} }{h} )
G = George's paiting rate ( \frac{ ft^{2} }{h} )
M = Mario's paiting rate ( \frac{ ft^{2} }{h} )

As the first statement says that they can work together, then:

T + G + M = Painting rate working together, that is the surface area they paint per hour.

Since the problem says that they last four hours painting a 600ft^{2} room, then we need to multiply the amount of hours times the painting rate that is equal the surface area of the room, so:

4(T + G + M) = 600

Applying a similar reasoning, the George and Mario's painting rate is:

0 + G + M 
Note that 0 implies that Tom didn't work in this case.

As they last eight hours painting the room, then:

8(0 + G + M) = 600

The same reasoning is applied to Tom and George working together. In this case 0 implies that Mario didn't work, so:

6(T + G + 0) = 600

We have a system of linear equations in three variables T, G, M:

<span>4(T+G+M)=600
8(0+G+M)=600
6(T+G+0)=600
</span>
Solving:

(1) T + G + M = 150
(2) G + M = 75
(3) T + G = 100

Substitute (3) in (1):
100 + M = 150 ∴ M = 50

Replace M in (2):
G + 50 = 75 ∴ G = 25

Substitute G in (3)
T + 25 = 100 ∴ T = 75

Then, the painting rates are:
Tom = 75 ( \frac{ ft^{2} }{h} )
George = 25 ( \frac{ ft^{2} }{h} )
Mario = 50 ( \frac{ ft^{2} }{h} )

<span>Solving for Time to determine how long it would take Tom to paint the room alone:
</span>
<span>Painted Area = Painting Rate×Time, so:

</span>Time Tom =  \frac{Painted Area}{Painting Rate (T)}
Time Tom = \frac{600}{75} = 8 hours
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