I set x-3 and 3x-13 equal to each other and then got x equal to 5. So, I believe the correct answer would be C.) 5
Make the x axis seconds and y axis floors. Your first point would be at (0,-2), then (1,3), then (2,8) and so on.
You could scale the axes just going by one
Answer:
a) x=3
b) z=10
c) P= 2
d) X=7
e) U=1
Step-by-step explanation:
Resolver una ecuación consiste en hallar los valores de la variable que hacen cierta la igualdad.
a) 2x= 6
El coeficiente es el número junto a la variable. En este caso, el coeficiente es 2. Para eliminar este número en la expresión 2x, debido a que la variable x esta multiplicada por 2, deberás dividir ambos lados de la ecuación entre 2, debido a que la operación opuesta de la multiplicación es la división.
(2x)÷2=6÷2
x= 3
Comprobar la solución de una ecuación se hace al remplazar la variable en una ecuación con el valor de la solución. La solución debería satisfacer la ecuación cuando se ingresa en esta.
En este caso:
2*3= 6
6=6
b) 10 + z= 20
En este caso se debe sumar o restar la constante que se encuentra acompañando a la variable en ambos lados de la ecuación de manera de aislar el término de la variable. En este caso:
10 - 10 + z= 20 -10
z= 10
Comprobación:
10 + z=20
10 + 10=20
20=20
c) P + 9= 11
P +9 - 9= 11 -9
P=2
Comprobación:
2 + 9= 11
11=11
d) 3X + 8 = 29
En este caso, se suma o resta la constante en ambos lados de la ecuación y luego se elimina el coeficiente de la variable mediante la división o multiplicación. Esto es:
3X + 8 - 8= 29 - 8
3X= 21
3X ÷3= 21÷3
X=7
Comprobación:
3*7 + 8=29
21+8=29
29=29
e) 2U + 8= 10
2U + 8 - 8= 10 -8
2U= 2
2U ÷2= 2÷2
U=1
Comprobación:
2*1 + 8= 10
2 + 8= 10
10=10
Answer:
Step-by-step explanation:
This is a super question and it is an excellent exercise for you. When I was teaching, once every term, I would ask my physics class to explain acceleration to a 7 year old. The stats favored the older women (mothers) who took the class. Almost none of the guys could do it. Here's why.
- The sentences had to be very short. They were barely 6 or 7 words long. They were complete sentences.
- The examples used had to be very simple. The secret to those mother's answers was they invariably picked something like a stop sign. They all knew that and they always got it right for those reasons.
You are trying to teach a seven or eight year old. Believe it or not, the first thing you have to do is check and see if they know their facts. Can they do 7+8 or 9+ 6 without hesitancy. If they can do those facts do they know the multiplication facts. 4 * 5 etc. They must know those things cold, or you are wasting your time. Don't ask me why. But you can't go on without those 2 fact types solid.
I take it you are trying to do word problems. The best thing you can do is teach them to read.
A man has a dime and a nickel and a penny. How much money does he have? Us a marker to underline the key statement.
a dime,
a nickel
a penny should be underlined. Don't ask for an answer - yet.
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Keep doing this problem over and over. You are not trying to get an answer. You are trying to get them to understand how to read a question
A person has just less than 4 quarters just less than 5 dimes and just less than 4 nickels. How many coins does he have. That's an important question because the grade three-er is going to have to know what less means.
That should get you started.
