Answer: No, x+3 is not a factor of 2x^2-2x-12
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Explanation:
Let p(x) = 2x^2 - 2x - 12
If we divide p(x) over (x-k), then the remainder is p(k). I'm using the remainder theorem. A special case of the remainder theorem is that if p(k) = 0, then x-k is a factor of p(x).
Compare x+3 = x-(-3) to x-k to find that k = -3.
Plug x = -3 into the function
p(x) = 2x^2 - 2x - 12
p(-3) = 2(-3)^2 - 2(-3) - 12
p(-3) = 12
We don't get 0 as a result so x+3 is not a factor of p(x) = 2x^2 - 2x - 12
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Let's see what happens when we factor p(x)
2x^2 - 2x - 12
2(x^2 - x - 6)
2(x - 3)(x + 2)
The factors here are 2, x-3 and x+2
2/5 + 2/4
8/20 = 10/20
8/20 + 10/20 = 18/20
18/20 = 9/10
9/10 = 0.9
Your answer is 9/10 or 0.9
Hope I helped!
Let me know if you need anything else
~ Zoe
Answer:
90 degrees
Step-by-step explanation:
If two angles are supplementary they are a linear pair which means they form a straight line, and if you know a straight line equals 180 degrees which is the total degrees of a triangle.
Now if you have two supplementary angles and they are congruent that means not only are they right angles but its half of 180 so you divide these pair of 2 by 180 giving you your total of 90 degrees.
Have a nice rest of your day !
