Answer:
2x+6-(x^2+6x+9)*pi
Step-by-step explanation:
2*(x+3) - (x+3)^2*pi
2x+6-(x^2+6x+9)*pi
um I think there are answer choices so I don't know if I have to keep going but that should be right
Is that considered two equations?
Answer:
Step-by-step explanation:
U right it’s not any of them and if u single I’m here
