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grigory [225]
3 years ago
11

2 plus 2/5 times 23 / 4

Mathematics
2 answers:
nexus9112 [7]3 years ago
7 0

Answer:

163/20 or 8.15

Step-by-step explanation:

well we are going to do PEMDAS

parentheses

exponents

multiplication/ division

addition/ subtraction

2 + 2/5 x 23/4 (i made the fractions into decimals)

2 + 6.15

163/20 or 8.15

raketka [301]3 years ago
5 0
The answer is 163/20 or 8.15 !
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Value of P: 3/15(p+10)=-15
ArbitrLikvidat [17]
<span>Step  1  :</span> 1 Simplify — 5 <span>Equation at the end of step  1  :</span> 1 (— • (p + 10)) - -15 = 0 5 <span>Step  2  :</span><span>Equation at the end of step  2  :</span> (p + 10) ———————— - -15 = 0 5 <span>Step  3  :</span>Rewriting the whole as an Equivalent Fraction :

<span> 3.1 </span>  Subtracting a whole from a fraction 

Rewrite the whole as a fraction using <span> 5 </span> as the denominator :

-15 -15 • 5 -15 = ——— = ——————— 1 5

<span>Equivalent fraction : </span>The fraction thus generated looks different but has the same value as the whole 

<span>Common denominator : </span>The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

<span> 3.2 </span>      Adding up the two equivalent fractions 
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

(p+10) - (-15 • 5) p + 85 —————————————————— = —————— 5 5 <span>Equation at the end of step  3  :</span> p + 85 —————— = 0 5 <span>Step  4  :</span>When a fraction equals zero :<span><span> 4.1 </span>   When a fraction equals zero ...</span>

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the <span>denominator, </span>Tiger multiplys both sides of the equation by the denominator.

Here's how:

p+85 ———— • 5 = 0 • 5 5

Now, on the left hand side, the <span> 5 </span> cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
   p+85  = 0

Solving a Single Variable Equation :

<span> 4.2 </span>     Solve  :    p+85 = 0<span> 

 </span>Subtract  85  from both sides of the equation :<span> 
 </span>                     p = -85 

One solution was found :                  <span> p = -85</span>
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