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2 years ago

Please can i have help

Mathematics

2 answers:

otez555 [7]2 years ago

5 0

Answer:

1:6ab

2: c^6x

3: 10y^7x

4:3g^4 h^5 x^4

AVprozaik [17]2 years ago

3 0

A)6ab
b) c^6
c) 10y^7
d) 12g^4h^5

Mark brainliest please

Hope this helps you

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A manufacturer has cube shaped cardboard boxes with an exact volume of 12000 cubic inches. What is the volum of the largest sphe

vladimir1956 [14]

Answer:

6283 in³

Step-by-step explanation:

The largest sphere that can fit into the cardboard box must have its diameter, d equal to the length, L of the cardboard box.

Since the cardboard box is in the shape of a cube, its volume V = L³

So, L = ∛V

Since V = 12000 in³,

L = ∛(12000 in³)

L= 22.89 in

So, the volume of the sphere, V' = 4πr³/3 where r = radius of cube = L/2

So, V = 4π(L/2)³/3

= 4πL³/8 × 3

= πL³/2 × 3

= πL³/6

= πV/6

= π12000/6

= 2000π

= 6283.19 in³

≅ 6283.2 in³

= 6283 in³ to the nearest whole cubic inch

6 0

3 years ago

Graph y=-|x+1| first answer gets brainly answer

padilas [110]

Answer:

See attachment

Step-by-step explanation:

The negative in front flips it over the y axis

The +1 moves it left

Have a great day!!!

(Also can I please have Brainliest, I need it to level up!)

4 0

2 years ago

Factoring expressions: 17x-34xy

Katarina [22]

17x(1-2y)

17x-34xy

because both expressions have a x, it would be easier to factor out the x first. but because 17 is a factor of 34 you can simply divide 34 by 17 and get 2. so you put it together to this,

17x(1-2y)

Because, 17x times 1 is 17x but 17x times -2y would be -32xy.

8 0

3 years ago

Read 2 more answers

What is the mathematical notation for absolute value?

alukav5142 [94]

Use vertical pipes around the value.

Example:

abs(-4) = |-4| = 4

4 0

3 years ago

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7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$

>> Therefore, your answers are x = -4 or x = 2.

Learn more about quadratic equations:

brainly.com/question/27638369

6 0

2 years ago

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