Answer:
I really dont know
Step-by-step explanation:
Answer:
-1
Step-by-step explanation:
Took the assignment! :)
The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.
Angles PQT and RQS are vertical angles and angles PQR and TQS are vertical angles.
angle PQS and TQR are straight angles
angles TQP and PQR form a linear pair. they are also adjacent by default. the other angles have these same features.
that should bout do it. hope it helped!
Answer:
?=19
x=30
Step-by-step explanation:
5/6x - 1/5x = 19
5(5/6x) - 6(1/5x) = 19
25/30x-6/30x=19
19/30x=19
19x=19(30)
19x=570
x= 570/19
x=30