Answer:
The point is at about (4.5, 100).
Step-by-step explanation:
Minka's line is p = 22t, which has a y-intercept of 0.
Kenji's line is p = 50 + 11t, which has a y-intercept of 50.
Find the line with y-intercept at 0 and the line with y-intercept at 50. Follow the two lines until they intersect. The point of intersection is about (4.5, 100).
You can find this point by setting the two equations equal to each other:
22t = 50 + 11t
Subtract 11t from both sides.
11t = 50
t = 50/11 ≈ 4.545
Then you can find the p value for this point by plugging t = 4.545 into either equation.
p = 22(4.545) = 99.99
p = 50 + 11(4.545) = 99.995
On the graph the point is about (4.5, 100).
11.22 is 33% of 34 if that is what youre asking
Answer: $30,904.49
Step-by-step explanation:
I’m not sure if I did this right but it was the same was as the other question
Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]
the area of each trapezoid is (v(t1)+v(t2))/2 times width
for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8
2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24
3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75
4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7
add them all up
0.8+2.24+1.75+0.7=5.49
5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
You do 4/1 divided by 2/9
4 2
_ divided by _
1 9
Equals 18
(You have to multiply by the reciprocal)
4/1 times 1/4
And
2/9 times 1/4
Hope I helped!!!
