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never [62]
4 years ago
13

Quick i need loads of help well not much

Mathematics
1 answer:
inna [77]4 years ago
4 0

Answer:

A= take away 3 b=??

Step-by-step explanation:

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The coordinates A(0,0) B(0,4) C(3,4) and D(3,0) are graphed and connected together. What 3 dimensional shape will be created whe
Anit [1.1K]
All you have to do is rotate the current dots, and bam.

6 0
3 years ago
In a casino, the chance of winning a certain game is 14.5%. If you play the game 20 times, what’s your best estimate for the num
EleoNora [17]
Expected number of wins=number of plays times the probability of winning

w=20(14.5/100)

w=20(0.145)

w=2.9

w≈3 

So you would expect to win 3 times out of 20 attempts (rounded to the nearest whole number of wins)
7 0
4 years ago
Kim is creating a mosaic in her garden. She finds the tile below and wants to know the missing side length ‘x’. Calculate the mi
GrogVix [38]

Answer:

x = 7.99 cm

Step-by-step explanation:

By applying cosine rule in the given triangle,

AC² = AB² + BC² - 2(AB)(AC)cosC

Substitute the measures of the sides and the angle in this formula,

x² = 6² + 10² - 2(6)(10)cos(53°)

x² = 36 + 100 - 72.217

x² = 63.782

x = √(63.782)

x = 7.99 cm

8 0
3 years ago
Five workers together can build a road in 20 days. Suppose every worker works at the same rate. Three workers work on the road f
Scilla [17]

Answer:

5 days

Step-by-step explanation:

This problem is an inverse proportion case. Having two variables: number of workers and time (in days); when we increase the number of workers, the time needed decreases; vice versa. Therefore, we can use the multiplication method: (workers * time) will always stay constant.

Let's say the time (in days) needed by the eleven workers is t,

5*20 = (3*10) + (14*t)

100 = 30+14t

70 = 14t

5 = t

It will take the eleven-workers 5 more days to finish the road.

8 0
2 years ago
What
Nataly_w [17]
I assume you want the equation to be solved, so this is a quadratic simultaneous equation.

y = x^2-x-3 ——— (1)
y = -3x+5 ——— (2)

Sub (1) into (2)
(This is the first three steps provided)

x^2-x-3 = -3x+5
0 = x^2+2x-8
0 = (x-2)(x+4) ——— (3)

Solve for x in (3):

x-2 = 0
x = 2

x+4 = 0
x = -4

Sub x into (2)

y = -3(2) + 5
y = -1

y = -3(-4) + 5
y = 17

Hence the solution sets are:

x=2, y=-1
x=-4, y=17
8 0
3 years ago
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