Question

What is the Equation of a line that passes through (-3,8) and (-2,9

Answer 1

Answer:

y = 16x + 41

Step-by-step explanation:

$(-3, 8) (-2, 9)\\(x^{1}, y^{1}) (x^{2}, y^{2})\\\\Calculate Slope: \\\\\frac{y^2 - y^1 }{x^2 - x^1 } \\9 - 8/-2 + 3\\= 16\\y= 16x + b\\(pick a point)\\(-2, 9)\\y = mx+b\\\\9 = 16*-2 + b\\9 = -32 + b\\9 (+32) = -32 (+32) + b\\41 = b\\\\Substitute variables into equation\\\\y = mx + b\\y = 16x + 41\\\\\\Hope this helps!!$

Answer 2

Answer:

Step-by-step explanation: