Answer the following question in complete sentences:

Mathematics

1 answer:

Olenka [21]3 years ago

6 0

Answer:

it creates outliers

Step-by-step explanation:

A gap in a dot plot is a certain range where no data exists for certain values, thus, creates values more or less than the data cluster, which can be defined by the word outlier

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Factor sec^2x-secx+tan^2x

marysya [2.9K]

Answer:

sec²(x) - sec(x) + tan²(x) = (sec(x) - 1)(2sec(x) + 1)

Step-by-step explanation:

sec²(x) - sec(x) + tan²(x) =

= sec²(x) - sec(x) + [sec²(x) - 1]

= sec²(x) - sec(x) + [(sec(x) + 1)(sec(x) - 1)]

= sec(x)[sec(x) - 1] + [(sec(x) + 1)(sec(x) - 1)]

= (sec(x) - 1)(sec(x) + sec(x) + 1)

= (sec(x) - 1)(2sec(x) + 1)

6 0

3 years ago

Please help me solve this

In-s [12.5K]

Step-by-step explanation:

Erase the dot points you already have. We are supposed to substitute those values in the right side of problem 1 into the function as x.

For example if x=-4

$- ( - 4) + 5 = 9$

If x=-2

$- ( - 2) + 5 = 7$

If x=0

$0 + 5 = 5$

$- 2 + 5 = 3$

$- 4 + 5 = 1$

So our point should be

-4,9

-2,7

0,5

-2,3

-4,1.

The range is all possible y values in a function. Since this is discrete and we are given the domain, our range will just be the y value of the points you graphed.

(9,7,5,3,1)

5 0

2 years ago

When the outliers are removed, how does the mean change? dot plot with 1 on 50, 1 on 76, 1 on 78, 2 on 79, 1 on 80, 1 on 81, 2 o

sveticcg [70]

We can plot this data on MS Excel and determine the distribution of these data reflected on the graph. Among these numbers, 50 is the outlier since it is very far from the other numbers ranging from 76 to 83. We can perform interquartile range to determine or verify the outliers in the data set. In this respect, we can see that there is not much distribution seen. The average of all data sets is equal to 96.25. When the outlier (50) is removed, we expect the mean to become higher since a low number was ommitted including high numbers only. Outliers are obtained from special causations such as human errors.