Answer:
The probability that they sit next to each other is 50%.
Step-by-step explanation:
Consider the provided information.
It is given that there are four seats within the row are first come, first served during boarding.
There are 4 seats and 2 customers (Karen and Georgia)
The total number of ways in which Karen and Georgia can sit is: 
Now if they will sit together, then consider Karen and Georgia as a single unit.
Thus, the number of ways in which they can sit together is: 
The required probability is:

Hence, the probability that they sit next to each other is 50%.
344.75 I did the math lol not that hard tbh
Answer:
Pretty sure it is C
Step-by-step explanation:
Answer:
kne-hnfd-vsq
Step-by-step explanation:
join this link
Answer:
Positive: (-3)4,(-1)2,(-4)8
Negative:(-10)5,(-2)9,(-6)3
Step-by-step explanation: