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rosijanka [135]
3 years ago
13

PLEASE HELP 45

Mathematics
1 answer:
Mamont248 [21]3 years ago
3 0

Answer:I believe the answer is true but not 100% sure Hope this helped

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Wite a numerical expression for the below problems. Simplify the expressions.
ziro4ka [17]

Answer:

1) 9

2) 34

Step-by-step explanation:

For the first one, it would be

= (6×3)/2

= 18/2

= 9

The second one is,

= 36- (12/6)

= 36 - 2

= 34

4 0
2 years ago
Enter the sum of numbers as a product of their GCF.75 + 90
Semmy [17]
The gcf of the numbers are 15
5 0
3 years ago
PLEASE HELP IM STUCK PLS
QveST [7]

Answer:

<u>The slope is -3.</u>

Step-by-step explanation:

The slope is the Rise/Run between the two points.  The change in y for every change in x.  Take the two points and calculate the:

RISE = (-6 - 3) = -9

RUN = (8 - 5) = 3

Rise/Run, or slope, is = -9/3 or -3

I graphed a line with slope of -3 and then added 18 to force the line to intersect the two given points.

3 0
2 years ago
Can someone pls help meee!!
Elena L [17]

Answer:

Hello! answer: 40

We know 1 angle is 50 degrees so that means the angle across will also be 50 degrees so that means 2 will be 40 degrees cause that is a complimentary angle and complimentary angles add up to 90 Hope this explains well!

7 0
3 years ago
Read 2 more answers
Factories A and B produce computers. Factory A produces 3 times as many computers as factory B. The probability that an item pro
OleMash [197]

Answer:

P(A∣D) = 0.667

Step-by-step explanation:

We are given;

P(A) = 3P(B)

P(D|A) = 0.03

P(D|B) = 0.045

Now, we want to find P(A∣D) which is the posterior probability that a computer comes from factory A when given that it is defective.

Using Bayes' Rule and Law of Total Probability, we will get;

P(A∣D) = [P(A) * P(D|A)]/[(P(A) * P(D|A)) + (P(B) * P(D|B))]

Plugging in the relevant values, we have;

P(A∣D) = [3P(B) * 0.03]/[(3P(B) * 0.03) + (P(B) * 0.045)]

P(A∣D) = [P(B)/P(B)] [0.09]/[0.09 + 0.045]

P(B) will cancel out to give;

P(A∣D) = 0.09/0.135

P(A∣D) = 0.667

7 0
3 years ago
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