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Lostsunrise [7]
3 years ago
15

Please help on this question

Mathematics
1 answer:
bearhunter [10]3 years ago
8 0
negative :))

hope it’s right
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Find a formula for the function whose graph is given below.
gayaneshka [121]
Y=(x-2)^2+3
^^^^^^^^^^^^^^^^
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3 years ago
4/6 in the lowest term helpppppppppp!!!!!!!
Agata [3.3K]

2/3 would be the answer hope this helps.

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3 years ago
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Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin
ozzi

Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let \mu = <em><u>mean duration of 15-sided union rugby games after the meeting.</u></em>

So, Null Hypothesis, H_0 : \mu \geq 185 minutes      {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, H_A : \mu < 185 minutes     {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean duration of 15-sided union rugby games = 179 min

            s = sample standard deviation = 12 minutes

            n = sample of 15-sided rugby games = 36

So, <u><em>the test statistics</em></u>  =  \frac{179-185}{\frac{12}{\sqrt{36} } }  ~ t_3_5

                                       =  -3

The value of t test statistics is -3.

<u>Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

6 0
3 years ago
Three times the difference of 5 and a number gives 30. Find the number.​
Temka [501]

Answer:

15

Step-by-step explanation:

we need to write the equation. I came up with....

3(5 - x) = 30

so take the 3 away from the 30. I think your not supose to do the 3 because it out of the ( ). the opppisite of multiplication is division. so...

3 divided by 30 =10

rewrite

(5 - x) = 10

take the 5 away. the oppisite of subbtraction is addition.

5 + 10 = 15

check your; plug in x

3(5 - 15) = 30  This equation looks true!

Hope this helped! Please mark as brainliest! Thanks

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3 years ago
Anyone wanna help me please
Art [367]

Answer:

the answer to this is x=16.1

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3 years ago
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