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Setler79 [48]
2 years ago
8

How much energy would a 15,000 g block of ice need to absorb in order to

Mathematics
1 answer:
Sergeu [11.5K]2 years ago
8 0

Answer:

The energy a 15,000 g block of ice will absorb in order to melt is 4995 kJ

Step-by-step explanation:

The question relates to the latent heat of fusion of ice, that is the heat absorbed by the solid ice to convert it to liquid water without changing its temperature.

The formula for the energy required to melt the ice is presented as follows;

Energy required = Mass, m × Latent heat of fusion, L_f, of ice

Hence, the mass, m, of the ice = 15,000 g

Latent heat of fusion, L_f, of ice = 333 J/g

Therefore;

Energy required = 15,000 g × 333 J/g = 4995000 J

Hence;

The energy a 15,000 g block of ice will absorb in order to melt = 4995000 J

1000 J = 1 kJ

1 J = 1/1000 kJ

Therefore, 4995000 J = (4995000 J)/(1000 J/kJ) = 4995 kJ.

Which gives;

The energy a 15,000 g block of ice will absorb in order to melt = 4995 kJ.

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Find the intercept of g(n)=-2(3n-1)(2n+1)
vaieri [72.5K]
To find the intercepts of this give function of g(n), we have to find both the points present on the axis. That is, X-Intercept axial or axis point and the Y-Intercept axial or axis point and apply the zero factor principle to get the actual points on the graph for both the respective intercepts. Let me make it simpler, by showing the whole process via the LaTeX interpreter equation editor.

The X-Intercept is that actual point present in the graphical interpretation where the Y-axis is taken as zero, this makes us to point out the position of X-Intercept points on its X-axis and Y-axis. Take the variable "n" as the variable of "x", it will not change any context or such, we can take any variables for calculations, it does not hinder the processing of Intercepts for the axial points on a graph.

\boxed{\mathbf{\therefore \quad -2(3x - 1)(2x + 1) = 0}}

By the zero factor principle, both of them can be separately calculated as a zero on their either sides of the expression.

\mathbf{\therefore \quad 3x - 1 = 0}

\mathbf{3x - 1 + 1 = 0 + 1}

\mathbf{3x = 1}

\mathbf{\dfrac{3x}{3} = \dfrac{1}{3}}

\mathbf{\therefore \quad x = \dfrac{1}{3}}

Similarly, for the second X-Intercept point for the value of 0 in the Y-axis or Y axial plane in a 2 dimensional Graphical representation is going to be, As per the zero factor principle:

\mathbf{\therefore \quad 2x + 1 = 0}

\mathbf{2x + 1 - 1 = 0 - 1}

\mathbf{2x = - 1}

\mathbf{\dfrac{2x}{2} = \dfrac{- 1}{2}}

\mathbf{\therefore \quad x = -\dfrac{1}{2}}

Then the X-Intercept here becomes with our provided points as:

\boxed{\mathbf{\underline{X-Intercept: \quad \Bigg(\dfrac{1}{3}, \: 0 \Bigg), \: \: \: \: \Bigg(-\dfrac{1}{2}, \: 0 \Bigg)}}}

Therefore, for our Y-Intercept axial point the X axial plane will instead turn out to be a value with zero on a Graphical representation to obtain the actual points for Y-axis and the Y-Intercept for x = 0 as a point on the graph itself.

Just substitute the value of "0" in "x" axis as a variable on the provided expression. Therefore:

\boxed{\mathbf{= -2(3 \times 0 - 1) (2 \times 0 + 1)}}

\mathbf{y = - 2 (0 - 1) (0 + 1)}

\mathbf{y = - 2 (- 1) (0 + 1)}

\mathbf{y = - 2 (- 1) \times 1}

\mathbf{y = 2 \times 1 \times 1}

\mathbf{\therefore \quad y = 2}

Then, the Y-Intercept would definitely be as per the X-axis lying on the point of zero.

\boxed{\mathbf{\underline{Y-Intercept: \quad \big(0, \: 2 \big)}}}

The final coordinating points for X-Intercept and Y-Intercept for their X-axis and Y-axis will be.

\boxed{\mathbf{\underline{X \: Intercepts: \: \: \Bigg(\dfrac{1}{3}, \: 0 \Bigg), \: \: \: \: \Bigg(-\dfrac{1}{2}, \: 0 \Bigg); \: \: Y \: Intercepts: \: \: \big(0, \: 2 \big)}}}

Hope it helps.
6 0
3 years ago
Find the range of f(x) = –x + 4 for the domain {–3, –2, –1, 1}.
marishachu [46]

Answer:

\boxed{ \{7, 6, 5, 3 \} }

Step-by-step explanation:

The domain is all possible values for x.

The range is all possible values for f(x) or y.

The domain given is {-3, -2, -1, 1}.

Plug x as {-3, -2, -1, 1} and find the f(x) or y values.

f(-3)=-(-3)+4=7\\f(-2)=-(-2)+4=6\\f(-1)=-(-1)+4=5\\f(1)=-(1)+4=3

The range is {7, 6, 5, 3}, when the domain is {-3, -2, -1, 1}.

5 0
2 years ago
the altitude of the hypotenuse of a right triangle divides the hypotenuse into segments of lengths 14 and 8. what is the length
lisov135 [29]

Answer:

B. 4\sqrt{7}

Step-by-step explanation:

The right triangle altitude theorem states that the altitude of a right angled triangles formed on the hypotenuse is equal to the geometric mean of the 2 line segments it creates.

This can be represented as:

h = \sqrt{(xy)}

Where,

h = the length of the altitude,

x and y are the lengths of the 2 segments formed.

Therefore, the length of the altitude = h = \sqrt{(14*8)}

h = \sqrt{112}

h = \sqrt{16}*\sqrt{7}

h = 4\sqrt{7}

3 0
3 years ago
Earl runs 90 meters in 60 seconds. How many meters does Earl run per second? Earl runs meters per second.
Anna007 [38]

Answer:

1 1/2 meters

Step-by-step explanation:

8 0
2 years ago
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Cindy has 26 nickels. She is getting rolls of nickels from the bank. She has enough money to get up to 10 rolls of nickels and e
Anna11 [10]
The answer is C I think 
4 0
2 years ago
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