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faust18 [17]
3 years ago
11

BRAINLIEST 5 STARS AND THANKS

Mathematics
1 answer:
WARRIOR [948]3 years ago
4 0

Answer:

8. 24+36+12= 72 in cubed

And yes it would fit because 72 is greater than 64

9. 2+21= 23 ft cubed

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☆pls help no one has helped me and I'm so confused! ​
motikmotik

Answer:

Step-by-step explanation:

a). \frac{5\pm\sqrt{-4}}{3} = \frac{5}{3}\pm \frac{\sqrt{-4}}{3}

               = \frac{5}{3}\pm\frac{2\sqrt{(-1)} }{3}

               = \frac{5}{3}\pm\frac{2i}{3} [Since, i = \sqrt{(-1)}]

b). \frac{10\pm\sqrt{-16}}{2} = \frac{10}{2}\pm \frac{\sqrt{-16}}{2}

                  = 5\pm \frac{4\sqrt{-1}}{2}

                  = 5 ± 2i [Since, i = \sqrt{(-1)}]

c). \frac{-3\pm \sqrt{-144}}{6} = -\frac{3}{6}\pm \frac{\sqrt{-144}}{6}

                    = -\frac{3}{6}\pm \frac{12\sqrt{-1}}{6}

                    = -\frac{1}{2}\pm 2\sqrt{-1}

                    = -\frac{1}{2}\pm 2i [Since, i = \sqrt{(-1)}]

4 0
3 years ago
What is the answer to <br>3(4x+6)+7x
Schach [20]
3(4x + 6) + 7x
12x + 18 + 7x
19x + 18 <==
4 0
3 years ago
Read 2 more answers
A random sample of n = 45 observations from a quantitative population produced a mean x = 2.5 and a standard deviation s = 0.26.
oee [108]

Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

H_0: \mu=2.4\\\\H_a:\mu> 2.4

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58

The degrees of freedom for this sample size are:

df=n-1=45-1=44

This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>2.5801)=0.0066

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

7 0
3 years ago
Please hurry. it's geometry.
Ainat [17]

That would be option A as the angles  and sides  ( the AS) have already been stated.

7 0
3 years ago
What is the mode of the data set?<br> (Please help)
Snowcat [4.5K]

Answer:

the number that occures the most is the answer

Step-by-step explanation:

7 0
3 years ago
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