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kaheart [24]
3 years ago
6

Which of the following describes how to translate the graph of y = Ixl to obtain the graph of y = lx + 1l - 2?

Mathematics
1 answer:
Rom4ik [11]3 years ago
7 0

Answer:

Shift left 1 and down 2

Step-by-step explanation:

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The area of a rectangular garden is given by the trinomial x2 + x – 42. What are the possible dimensions of the rectangle? Use f
Murrr4er [49]

Answer:

Step-by-step explanation:

Hello, please consider the following.

x^2+x-42\\\\\text{The sum of the zeroes is -1=-7+6 and the product is -42=-7*6.}\\\\\text{So, we can factorise.}\\\\x^2+x-42\\\\=x^2+7x-6x-42\\\\=x(x+7)-6(x+7)\\\\=(x+7)(x-6)

So, the possible dimensions of the rectangle are (x+7) and (x-6).

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Which of the x-values are solutions to the following inequality? x< 100 Help ASAP
netineya [11]

Answer:

x = - infinity to 99

Step-by-step explanation:

The values of x must less than 100.

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3 years ago
Please help, i will give brainliest to whos first
Wittaler [7]

Thanks with all of my heart!

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3 years ago
Please help i dont wanna fail this time
mezya [45]

Answer:

Step-by-step explanation:

So...

you would add -4 and -2 1/2 giving the total of -6 1/2.

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I need help with this
andre [41]

Answer:

  f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}

Step-by-step explanation:

Each vertical asymptote corresponds to a zero in the denominator. When the function does not change sign from one side of the asymptote to the other, the factor has even degree. The vertical asymptote at x=-4 corresponds to a denominator factor of (x+4). The one at x=2 corresponds to a denominator factor of (x-2)², because the function does not change sign there.

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Each zero corresponds to a numerator factor that is zero at that point. Again, if the sign doesn't change either side of that zero, then the factor has even multiplicity. The zero at x=1 corresponds to a numerator factor of (x-1)².

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Each "hole" in the function corresponds to numerator and denominator factors that are equal and both zero at that point. The hole at x=-3 corresponds to numerator and denominator factors of (x-3).

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Taken altogether, these factors give us the function ...

  \boxed{f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}}

8 0
3 years ago
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