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Alecsey [184]
2 years ago
8

PLEASE HELP!!! with only mean and median given can you find which other data has a greater interquartile range?

Mathematics
1 answer:
Aleksandr-060686 [28]2 years ago
4 0
I would say yes. I just did mean and median mode and range for the 3rd quarter of the school year so I think it’s a yes
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A table has an area of 12 ft squared and a perimeter of 16 ft. What are the dimensions of the table?
Likurg_2 [28]
P=2x+2y, y=(p-2x)/2

a=xy, using y found above in this equation gives you:

a=(px-2x^2)/2  we are told a=12 and p=16 so

12=(16x-2x^2)/2

24=16x-2x^2

2x^2-16x+24=0

2x^2-12x-4x+24=0

2x(x-6)-4(x-6)=0

(2x-4)(x-6)=0

2(x-2)(x-6)=0

So the table is 2 ft by 6 ft.
7 0
3 years ago
Read 2 more answers
Can someone help me with this pls. I’ll give brainliest
nasty-shy [4]

Answer:

26

Step-by-step explanation:

a triangle is 180 degrees add 120 + 34 to get 154

180 -154 = 26

3 0
2 years ago
E<br> Homework: 1-7 HW<br> Simplify the expression.<br> 8(5+t) - 2(t+1)<br> 8(5 + t) - 2(t+1)=
lys-0071 [83]

Hi, I'm happy to help!

To simplify this expression, we need to first use the order of operations <u>(Parenthesis, Exponents, Multiplication or Division (Left to Right), and Addition or Subtraction (Left to Right)</u>), then combine like terms. (<u>80,40,57</u>, or <u>6t, 8t, 98t</u>, or<u> 2t²,7t²,83t²</u>)

When a number is next to parenthesis with no sign, it means we are using multiplication. We can change this expression to look like this, by changing all the numbers next to the parenthesis with no sign, to one with a multiplication sign.

8(5+t) - 2(t+1) 8(5 + t) - 2(t+1)=

8×(5+t) - 2×(t+1)× 8×(5 + t) - 2×(t+1)=

We start with parenthesis and solve everything inside of those, but, because everything inside the parenthesis are unlike terms, we cannot combine them.

Next, We look for any exponents (x²). There are none in this equation.

We then look for multiplication or division. There is a lot of multiplication, so we start solving that from left to right.

8×(5+t) - 2×(t+1)× 8×(5 + t) - 2×(t+1)=

40+8t - 2×(t+1)× 8×(5 + t) - 2×(t+1)=

40+8t - 2×(t+1)× 8×(5 + t) - 2×(t+1)=

(40+8t) - (2t+2)× 8×(5 + t) - 2×(t+1)=

(40+8t) - (2t+2)× 8×(5 + t) - 2×(t+1)=

(40+8t) - (16t+16)×(5 + t) - 2×(t+1)=

(40+8t) - (16t+16)×(5 + t) - 2×(t+1)=

(40+8t) - (80t+16t²+80+16t) - 2×(t+1)=

(40+8t) - (80t+16t²+80+16t) - 2×(t+1)=

(40+8t) - (80t+16t²+80+16t) - (2t+2)=

(40+8t) - (80t+16t²+80+16t) - (2t+2)=

Now, before we do anything else, we need to recheck the parenthesis, now that they have changed. We can further simplify the middle parenthesis by adding together like terms.

(40+8t) - (80t+16t²+80+16t) - (2t+2)=

(40+8t) - ((80t+16t)+16t²+80) - (2t+2)=

(40+8t) - (96t+16t²+80) - (2t+2)=

(40+8t) - (96t+16t²+80) - (2t+2)=

Now, we look for addition or subtraction of like terms. We can now remove the parenthesis, since everything inside of the last two parenthesis is negative, we turn it negative, as long as we only combine the like terms.

40+8t - 96t-16t²-80 - 2t-2=

Once we find like terms, we can rearrange the expression.

(40-80-2)+8t - 96t+16t² - 2t

(-42)+8t - 96t-16t² - 2t

(-42)+8t - 96t-16t² - 2t

(-42)+(8t-96t-2t)-16t²

(-42)+(-90t)-16t²

(-42)+(-90t)-16t²

This doesn't have any like terms, so we don't alter it.

(122)+(-90t)-16t²

We can now remove the parenthesis.

122-90t-16t²

Since there are no more like terms this is the furthest we can simplify. We can then rearrange the expression to be arranged completely correct.

-16t²-90t-42

I hope this was helpful, keep learning! :D

4 0
3 years ago
Joe has $70 in a savings account. The interest rate is 10% per year and is not compounded,
sladkih [1.3K]

Answer:

$28

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 10%/100 = 0.1 per year,

then, solving our equation

I = 70 × 0.1 × 4 = 28

I = $ 28.00

The simple interest accumulated

on a principal of $ 70.00

at a rate of 10% per year

for 4 years is $ 28.00.

8 0
2 years ago
Log (x) + log (x + 5) = log (6 x + 12) <br><br> I need the answer asap
kiruha [24]
It’s b I had it in my test
5 0
3 years ago
Read 2 more answers
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