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Oksi-84 [34.3K]
2 years ago
9

How Do I Find The Answer To 320 = 3x + 16

Mathematics
1 answer:
ruslelena [56]2 years ago
7 0

。☆✼★ ━━━━━━━━━━━━━━  ☾  

320 = 3x + 16

-16 from both sides

304 = 3x

/3 on both sides

x = 304/3

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

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Which two integers are 7 units away from the number 5 on a number line? A-2 and 2 O B-2 and c. -- and D. -2 and​
Sloan [31]

Answer:

-2 and 12

Step-by-step explanation:

To find the two numbers which are 7 units away from 5, add 7 to 5 and subtract 7 from 5

5+7 = 12

5-7 = -2

5 0
2 years ago
A sum of $4000 is invested at 5.5% interest per year. Find the amount of time needed to double the money if it’s compounded mont
musickatia [10]

9514 1404 393

Answer:

  C)  12y 8m

Step-by-step explanation:

The amount of principal P at compound monthly at interest rate r per year is given by ...

  A = P(1 +r/12)^(12t) . . . . after t years

Here, we want to find t, so ...

  A/P = (1 +r/12)^(12t)

  log(A/P) = (12t)·log(1 +r/12)

  t = log(A/P)/(12·log(1 +r/12))

Filling in the given values, we find t to be ...

  t = log(8000/4000)/(12·log(1 +0.055/12)) ≈ 12.6315 ≈ 12 years 7.6 months

It will take about 12 years 8 months to double the money.

8 0
3 years ago
Hey can you please help me posted picture of question :)
harina [27]
Y=(x-3)^2+36
Using (a-b)^2=a^2-2ab+b^2, with a=x and b=3
y=(x)^2-2(x)(3)+(3)^2+36
y=x^2-6x+9+36
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4 0
3 years ago
93000000 in standard form
noname [10]
It’s already in standard form: 93,000,000

If we would put it in scientific notation though, it would be: 9.3 x10 ^7 (to the power of 7)
3 0
2 years ago
What is the distance between the points (2,10) and (-6, 4) on the coordinate
stellarik [79]

Answer:

The distance between the given points (2,10) and (-6, 4) on the coordinate  plane is 10units

Therefore distance s=10 units

Step-by-step explanation:

Given points are (2,10) and (-6, 4) on the coordinate plane

To distance between the given points :

The distance formula is s=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} units

Let (x_1,y_1) ,(x_2,y_2) be the given points (2,10) and (-6, 4) respectively

Now substituting the values in the distance formula  we get

s=\sqrt{(-6-2)^2+(4-10)^2}

=\sqrt{(-8)^2+(-6)^2}

=\sqrt{8^2+6^2}

=\sqrt{64+36}

=\sqrt{100}

=10

Therefore s=10 units

The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units

5 0
3 years ago
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