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3 years ago

6

Suppose the shipping company were packing balls with a diameter of 2 inches instead of cubes. Would the large box hold more ball

s or fewer balls than boxes? Explain your answer.
________________________________________________________________________________________

1 answer:

Roman55 [17]3 years ago

8 0

Answer:

More

Step-by-step explanation:

Because the absence of corners allows more space for more balls

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Mike used the computation StartFraction 7 Over (6 + 8 + 7) almost-equals 0.33 = 33 percent to find the percentage of eighth-grad

snow_tiger [21]

Answer: option B

Step-by-step explanation:

i took the test lol

3 0

3 years ago

How many zero pairs must be added to the function

MakcuM [25]

1 zero pair of 25 was added to bring given function into vertex form.

<h3>What is a Zero Pair ?</h3>

A zero Pair is the set of two numbers which when added together gives 0.

The function given is

f(x) = x² -10x -4

To convert it into the vertex form

y = a(x-h)² +k

f(x) = x² -10x +25 -25 -4

f(x) = x² -10x +5² -25-4

f(x) = (x-5)² -29

Therefore this is the given function's vertex form and

1 zero pair of 25 was added to bring it into that.

Therefore Option D is the answer.

To know more about Zero Pair

brainly.com/question/5567379

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3 0

2 years ago

Holly has a credit limit of $2,500 on her credit card. She had a previous balance of $103.23

pochemuha

Step-by-step explanation:

$103.23

$100

$45.34

+_____

=248.57

3 0

2 years ago

(1 point) a tank contains 1060 l of pure water. a solution that contains 0.06 kg of sugar per liter enters the tank at the rate

kirill115 [55]

(a) There is 0 kg of sugar in the tank at the beginning since it contains pure water at the start. The sugar only comes from the solution.

(b)

$S' = f(t,S) = \left(0.06 \dfrac{\text{kg}}{\text{L}}\right)\left(9\dfrac{\text{L}}{\text{min}}\right) - \left(\dfrac{S}{1060} \dfrac{\text{kg}}{\text{L}}\right)\left(9\dfrac{\text{L}}{\text{min}}\right) \ \Rightarrow \\ \\ S' = 0.54 \text{ kg}/\text{min} - \dfrac{9S}{1060}$

So yes, you enter S' = 0.54 - (9S/1060)

(c)

$\displaystyle\frac{dS}{dt} = 0.54 - \frac{9S}{1060} \ \Rightarrow\ \frac{dS}{dt} = \frac{572.4 - 9S}{1060}\ \Rightarrow\ \dfrac{dS}{572.4 - 9S} = \frac{1}{1060} dt\ \Rightarrow \\ \\
\int \dfrac{dS}{572.4 - 9S} = \int \frac{1}{1060} dt\ \Rightarrow\textstyle\ -\frac{1}{9}\ln|572.4 - 9S| = \frac{1}{1060}t + C \\ \\
S(0) = 0 \ \Rightarrow\ -\frac{1}{9}\ln|572.4 - 0| = \frac{1}{1060}(0) + C\ \Rightarrow\ C = -\frac{1}{9} \ln 572.4$

$-\frac{1}{9}\ln|572.4 - 9S| = \frac{1}{1060}t -\frac{1}{9} \ln 572.4\ \Rightarrow \\ \\
\ln|572.4 - 9S| = \ln 572.4 - \frac{9}{1060}t \ \Rightarrow \\ \\
|572.4 - 9S| = e^{\ln 572.4 - 9t/1060}\ \Rightarrow \\ \\
572.4 - 9S= \pm 572.4 e^{-9t/1060}\ \Rightarrow \\ \\
S = \frac{-1}{9}\left(-572.4 \pm 572.4 e^{-9t/1060}\right)$

But only (+) satisfies $S(0) = 0$

$S= -\frac{1}{9}\left(-572.4 + 572.4 e^{-9t/1060}\right) \\ \\
S= 63.6 - 63.6 e^{-9t/1060}\text{ kg}$

Enter in S = 63.6 - 63.6 * e^(-9t/1060)

3 0

3 years ago

Can anyone help. Thanks

Ray Of Light [21]

Answer:

Option C

please see the attached picture for full solution

hope it helps..

Good luck on your assignment...

8 0

4 years ago