Cindy types 180 words in 2 minutes

Monique spends $28 and buys a pair of socks and a headband for each day of the week each headband costs $2.50 and all the cost t

pav-90 [236]

Answer:

$10.50 is spent on socks

Step-by-step explanation:

for 7 days, monique would spend $17.50 on headbands and $10.50 on socks.

7 0

3 years ago

Lisa bought some books. She spent a total of $45 after a discount of $6 off of her total purchase. Each book cost $3. How many b

elena55 [62]

Answer:

She spent 17 books

Equation: 45+6 = 51 and 51/3 = 17 books

8 0

3 years ago

What is the slope of a relation with ordered pairs of (-5, 3) and (4.1).

Georgia [21]

3-1 /-5-4
2/-9
-2/9 is the answer

5 0

3 years ago

A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as

Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let X = number of seconds in the batch.

The probability of the random variable X is, p = 0.31.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

$P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888$

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

$=1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776$

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

$={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453$

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0

3 years ago

Choose the graph of the function g(x) = 2 x 4^x

dexar [7]

Answer:

its B

Step-by-step explanation:

hope it helped you

8 0

3 years ago