Question

Please help I don’t know the answer :(

Answer 1

Answer:

When x=8, y=-6. When x=10, y=0

Step-by-step explanation:

$y=3x-30\\x^2+y^2=100$

You can plug the given y value into the second equation to get:

$x^2+(3x-30)^2=100\\x^2+9x^2-180x+900=100\\10x^2-180x+800=0\\10(x^2-18x+80)=0\\10(x-8)(x+10)=0\\x= 8, 10\\y= -6, 0$

Hope this helps!

Answer 2

-6,0 is the answer for this