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Elanso [62]
3 years ago
14

Your grade point average is 3.48. How can you write your grade point average as a fraction?

Mathematics
2 answers:
Colt1911 [192]3 years ago
8 0

Answer:

87/25

Step-by-step explanation:

looked it up hope it helps

pychu [463]3 years ago
3 0

Answer:

3.48/1

Step-by-step explanation:

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Which of these is equal to ⅔ × ¾ × ⅗?
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Answer:

3/10

Step-by-step explanation:

Just multiply all of the numerators (top numbers)  and then multiple all of the denominators (bottom numbers)

2/3x3/4x3/5  would be 18/60 Then take any number that is a factor to both 18 and 60 and divide both numbers by that factor.  I could use 2 or 3 or 6 because both 18 and 60 is divisible by any of these numbers.  I will choose 3.  I will divide the top and bottom of 18/60 by 3 to get 6/20, now I will divide the top and bottom of that number by 2 to get 3/10

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2 years ago
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A child's sandbox has a length of 5 metres and a width of 4 metres. A uniform sidewalk is to be built around the sandbox with pa
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3 years ago
Please answer : <br> (File below)
mars1129 [50]

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a

Step-by-step explanation:

4 0
2 years ago
What is tan angle QTR if line PR is tangent to circle T at Q, and TS = 1 cm?
lions [1.4K]
Tangent = opposite / adjacent

In the diagram:
TQ is the short leg or the opposite
QR is the long leg or the adjacent
TR is the hypotenuse. TS is part of the hypotenuse.

Tan(QTR) = TQ / QR

TS = 1 ; TQ = TS  so, TQ = 1

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3 0
3 years ago
Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel
Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

\frac{40}{400}=0.10

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

P(X=x)=^nC_xp^x(1-p)^{n-x}

We need to find P(X ≤ 3)

P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\

P(X\leq3) =0.944444369992\approx 0.94

Hence, the required probability is 0.94

4 0
2 years ago
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