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max2010maxim [7]
3 years ago
8

The following are the ages (years) of 5 people in a room: 23, 15, 17,23, 23 A person enters the room. The mean age of the 6 peop

le is now 19. What is the age of the person who entered the room?
Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
3 0

13 years

Step-by-step explanation:

17 + 15 + 23 + 23 + 23 =101 / 5 = 20.2

Mean before was 20.2

In order for the mean to be 19, all those numbers would have to add up 114 to be divided by 6 and have a mean of 19

114 / 6 = 19

114-101 = 13 is that number

17 + 15 + 23 + 23 + 23 + 13 = 114 / 6 = 19

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a square pyramid has a height of 14 cm and a base side length of 7 cm. What is the volume of the pyramid. Show work
Brut [27]

Step-by-step explanation:

The volume of a pyramid or cone is:

V = ⅓ Ah

where A is the area of the base and h is the height.

The pyramid has a square base, so:

A = s²

A = (7 cm)²

A = 49 cm²

The height is 14 cm, so the volume is:

V = ⅓ (49 cm²) (14 cm)

V = 686/3 cm³

V ≈ 228.67 cm³

7 0
3 years ago
Solve, using the substitution method.
ss7ja [257]

Answer:

(-6,-5)

Step-by-step explanation:

X+y=-11

solve for x

x=-11-y

substiute x value into 2nd equation

2x-3y=3

2(-11-y)-3y=3

-22-2y-3y=3

-5y=25

y=-5

substitute -5 for y in either equation to find x

x+y=-11

x+-5=-11

x=-6

8 0
2 years ago
Can Ny body help pls​
Maslowich

Answer:

Thank god im virtual

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Pleaseee help I’m so close to passing math
kobusy [5.1K]

Answer:

it'll be the first one. in the sentence it says that Adult is MORE

3 0
2 years ago
How to I solve problem 1?
Verdich [7]
#1

The uniforms are numbered 0, 1, 2, ..., 99. That's 100 numbers. Half of them are odd and half of them are even. So the probability that any one of the uniforms is odd is 1/2 just like the probability that any one uniform is even is 1/2.

(a) The numbers on the uniforms are independent of one another. That is, the number of her cross-country uniform does not in any way determine the number on her basketball uniform and vice versa. This means that we can find the probability that each is odd and multiply these together using what is called the counting principle. The probability that all are odd is:
(1/2)(1/2)(1/2)=1/8

(b) This is done the same way we did part (a). Since the probability of any one uniform being odd is the same as it being even (1/2), the answer here is the same: (1/2)(1/2)(1/2)=1/8

(c) This problem differs from that in (a) and (b). There is only one way for all three uniforms to be odd numbers: (odd, odd, odd) or all even (even, even, even). However, there are multiple ways for the uniforms to be two odd and one even. If the uniforms are listed in order: cross-country, basketball, softball we can get exactly one even in any of three ways:
even, odd, odd
odd, even, odd
odd, odd, even
The probability for any one of these possibilities is (1/2)(1/2)(1/2)=1/8 but since there are three way the probability that we get even exactly once is equal to (3)(1/8) = 3/8
7 0
3 years ago
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