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Lorico [155]
2 years ago
13

1, 2,5,6,9,... what’s the pattern

Mathematics
1 answer:
sleet_krkn [62]2 years ago
8 0

Answer:

+1+3

Step-by-step explanation:

1 +1=2

2+3=5

5+1=6

6+3=9

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Describe a relationship in which it would be reasonable to have a negative number in the domain or
Aliun [14]

Answer:

Relationship between temperature at different times of the day during the Winter period in places like Alaska and Minnesota in the USA.

Step-by-step explanation:

An example of a relationship that would have a negative number in the domain or range would be the relationship between the temperature at different times of the day during the snow period in the winter. It's well known that in places like Alaska and Minnesota in the USA, that during the winter when there's very heavy snow, the average temperature is usually below 0°C. The temperature is the dependent variable and is most likely negative in those 2 states and thus the range would have negative numbers.

7 0
3 years ago
PLZ HELP!!!!!!!!
nekit [7.7K]

Answer:

B. Function 2

Step-by-step explanation:

Line P gradient is

Gradient = rise/run

= 1/4

Negative slope so gradient is - 1/4

Out of all the gradient, the lowest value has to be function 2 or line p & not 1/4r-5 because when r is 1 we get a gradient of 1.

-1/4xr - 5

-1/4x1 - 5

-1/4-5

-1/-1 = 1

Plus, 1 is greater than - 1/4 or - 0.25.

8 0
2 years ago
Read 2 more answers
Which equation has the same slope as y = -5x - 4?
Sholpan [36]

Answer: Any equation that has a -5 before the x will have the same slope. Some examples could be:

y= -5x

y = -5x + 100

y = -5x - 3

6 0
3 years ago
Read 2 more answers
What is 2 1/6 plus 3 and 1/4
Alex777 [14]
5 5/12

(2+3) 1/6 + 1/4=

5 5/12
5 0
3 years ago
Find the vector projection of B onto A if A = 5i + 11j – 2k,B = 4i + 7k​
valkas [14]

Answer:

\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\

Step-by-step explanation:

Given A = 5i + 11j – 2k and B = 4i + 7k​, the vector projection of B unto a is expressed as proj_ab = \dfrac{b.a}{||a||^2} * a

b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)

note that i.i = j.j = k.k  =1

b.a = 5(4)+11(0)-2(7)

b.a = 20-14

b.a = 6

||a|| = √5²+11²+(-2)²

||a|| = √25+121+4

||a|| = √130

square both sides

||a||² = (√130)

||a||²  = 130

proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\

<em>Hence the projection of b unto a is expressed as </em>\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\<em></em>

7 0
3 years ago
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