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Strike441 [17]
3 years ago
5

Given the equation (x - 1) ^ 2 + (y + 20) ^ 2 = 196 identify the center and radius

Mathematics
1 answer:
Dima020 [189]3 years ago
3 0

Answer & Step-by-step explanation:

In order to solve this problem, it  is important that we know the original form of this equation.

<em>(x - x1)² + (y - y1)² = r²</em>

The equation we are given is: <em>(x - 1)² + (y + 20)² = 196</em>

Now that we know the original equation and the given equation, then we can conclude that the center of the circle is (1, -20). We can find the radius by calculating the square root of 196.

√196 = 14

So, the radius is 14.

Now, based on the given information, we know that the center of the circle is (1, -20) and the radius of the circle is 14.

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A rectangle is drawn so that the width is 3 feet shorter than the length. The area of the rectangle is 70 square feet. Find the
Vedmedyk [2.9K]

Answer:

The length of the rectangle (l) = 10 cm

The width of the rectangle (w) = 7 cm

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Let 'x' be the length of the rectangle

Given that the width is 3 feet shorter than the length

The width of the rectangle = x -3

Area of the rectangle = length × width

<u><em>Step(ii):-</em></u>

Area of the rectangle = length × width

                                  = x ( x-3)

Given that the area of the rectangle = 70 square feet

                       x ( x-3) = 70

              ⇒   x² - 3x - 70 =0

              ⇒  x² - 10 x + 7 x - 70 =0

             ⇒  x (x -10) +7( x-10) =0

            ⇒ ( x+7) ( x-10) = 0

           ⇒  x =-7 and x=10

<u><em>Final answer:</em></u>-

we choose x=10

The length of the rectangle (l) = 10 cm

The width of the rectangle (w) = 7 cm

8 0
3 years ago
how high up on a building will 15 foot ladder reach if the foot of the ladder is placed 5 feet from the building? (be sure to in
mezya [45]
Use the Pythagorean theorem:
5^2+x^2=15^2 \\&#10;25+x^2=225 \\&#10;x^2=225-25 \\&#10;x^2=200 \\&#10;x=\sqrt{200} \\&#10;x=\sqrt{100 \times 2} \\&#10;x=10\sqrt{2} \\&#10;x \approx 14.14

The ladder will reach approximately 14.14 feet (exactly 10√2 feet) up on the building.

3 0
3 years ago
Pls help i need to find the area again
valentina_108 [34]

Answer:

if you have discord i could help you more

Step-by-step explanation:

3 0
3 years ago
Find MN.<br> 4x+19=6x-7<br> Please and thank you.
Sunny_sXe [5.5K]

Answer:

MN = 71

Step-by-step explanation:

You first gotta know the value of x by putting both equations in line!

4x + 19 = 6x - 7

4(13) + 19 = 6(13) - 7

52 + 19 = 78 - 7

71 = 71

<u>Answer:</u> x = 13

Then we already have the length of MN!

<u>Answer:</u> MN = 71

4 0
3 years ago
The bearing from the Pine Knob fire tower to the Colt Station fire tower is N 65°E and the two towers are 30 kilometers apart. A
Novay_Z [31]

Answer:

The distance of fire from Pine Knob fire tower is 42.43 km

The distance of fire from Colt Station fire tower is 15.53 km

Step-by-step explanation:

Consider point A as Pine Knob fire tower and Point B as Colt Station fire tower. So the distance between both towers that is AB is 30 km.  

Now both fire tower  are located at a bearing of N65°E. That is at point A from north, Colt station fire tower is located at an angle of 65° towards east.

From ranger on Pine knob tower, fire spotted makes bearing of N80°E. That is at point A from north fire is located at an angle of 80° towards east.

Similarly, from ranger on Pine knob tower, fire spotted makes bearing of S70°E. That is at point B from south fire is located at an angle of 70° towards east.  

Now calculate \theta_{1}=\angle BAC and \theta_{2}=\angle ABD as follows,  

For \theta_{1}=\angle BAC

\angle XAC=\angle XAB+\angle BAC

\therefore 80\degree=65\degree+\angle BAC

\therefore \angle BAC=15\degree

For \theta_{2}=\angle ABD

By using alternate angle property,

\ angle XAB =\angle ABD=65\degree

Refer attachment 1.  

From diagram consider the triangle ABC. To find the third angle that is \angle BAC can be calculated by using angle sum property of triangle.  

\angle BAC+\angle ABC+\angle BCA=180\degree

\therefore15\degree +135\degree +\angle BCA=180\degree

\therefore \angle BCA=30\degree

Refer attachment 2.  

Sine rule for the \Delta ABCcan be applied as follows,  

\ddfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c}

Substituting the values,

\dfrac{\sin 15}{a}=\dfrac{\sin 135}{b}=\dfrac{\sin 30}{30}

Now distance AC and BC can be calculated as follows,  

For distance AC,  

\dfrac{\sin 135}{b}=\dfrac{\sin 30}{30}

Cross multiplying,  

30\times\sin 135=b\times\sin 30

\dfrac{30\times \sin 135}{\sin 30}=b

b=42.43\:km

The distance of fire from Pine Knob fire tower is 42.43 km

For distance BC,  

\dfrac{\sin 15}{a}=\dfrac{\sin 135}{42.43}

Cross multiplying,  

42.43\times\sin 15=a\times\sin 135

\dfrac{42.43\times \sin 15}{\sin 135}=a

a=15.53\:km

The distance of fire from Pine Knob fire tower is 15.53 km

6 0
3 years ago
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