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dimulka [17.4K]
2 years ago
9

I need help with this!

Mathematics
1 answer:
umka21 [38]2 years ago
5 0

It’s probably too late but

Point M is now at (7,1)

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I need help with all please!!
Olenka [21]

Answer:

1. D

2.C

3. A

4.B

5.C

6. C? or D(i think c cause it's 3 places but it can be d because the 0 is just a placeholder)

7.C

8.C

Step-by-step explanation:

3 0
3 years ago
If he pays $46.80 for one year. He receives one magazine each month for 12 months. Find the dollars he pays for each
pochemuha

Answer:

Each magazine costs 3.90

Step-by-step explanation:

Take the total cost and divide by the number of magazines

46.80/12

3.90

6 0
3 years ago
Read 2 more answers
Quadratic equations: Factoring
stellarik [79]
Remember
if ab=0, then assume that a and b equal 0

factor out common term
comon term in 6x^2 and 15x is 3x
3x(2x)+3x(5)=0
3x(2x+5)=0
set each to zero
3x=0
x=0

2x+5=0
2x=-5
x=-5/2


x=-5/2 and 0
6 0
2 years ago
Solve the rational equation 1/n-4 - 2/n = 3/4-n
Leokris [45]

Answer:

n=4

Step-by-step explanation:

Given equation: \[\frac{1}{n-4}-\frac{2}{n}=\frac{3}{4-n}\]

Simplifying the Left Hand Side of the equation by taking the LCM of the denominator terms:

\[\frac{n}{n*(n-4)}-\frac{2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{n - 2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{n - 2n + 8}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{8 - n}{n*(n-4)}=\frac{3}{4-n}\]

=> \[(8-n)*(4-n) =n*(n-4)*3\]

=> \[n-8 =3n\]

=> \[2n =8\]

=> n = 4

5 0
3 years ago
What is the sum of the polynomials? (6x+7x+x^2)+(2x^2-3x)
Trava [24]

Answer:

3x^2 + 10x

Step-by-step explanation:

4 0
2 years ago
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