Answer:
![P(x)=(x+9)(x^2-7x+52)+3](https://tex.z-dn.net/?f=P%28x%29%3D%28x%2B9%29%28x%5E2-7x%2B52%29%2B3)
Step-by-step explanation:
We are given that
![P(x)=x^3+2x^2-11x+471](https://tex.z-dn.net/?f=P%28x%29%3Dx%5E3%2B2x%5E2-11x%2B471)
![d(x)=x+9](https://tex.z-dn.net/?f=d%28x%29%3Dx%2B9)
We have to find the value of Q(x) and Remainder R(x).
Quotient, ![Q(x)=x^2-7x+52](https://tex.z-dn.net/?f=Q%28x%29%3Dx%5E2-7x%2B52)
Remainder,![R(x)=3](https://tex.z-dn.net/?f=R%28x%29%3D3)
We know that
![Dividend=Divisor\times Quotient+Remainder](https://tex.z-dn.net/?f=Dividend%3DDivisor%5Ctimes%20Quotient%2BRemainder)
![P(x)=(x+9)(x^2-7x+52)+3](https://tex.z-dn.net/?f=P%28x%29%3D%28x%2B9%29%28x%5E2-7x%2B52%29%2B3)
Answer:
51 cm^2
Step-by-step explanation:
13.5/9 = 1.5
so DEF is 1.5 times bigger than ABC
so 34 x 1.5 = 51
I’m not sure if this is actually a strategy but can I get brainliest please. If I’m not allowed to use a calculator then I would covert the decimals to fractions. I would covert them to the simplest fractions before multiplying so that the answer is as closest to its simplest form as possible.
Answer:
the answer for this question will be -13
<u>Solution</u>:
It is given that length of a rectangular room is 6.9 m and its width is 9.6 m.
So We have ;
- Length of Rectangular room = 6.9 m
- Length of Rectangular room = 6.9 m Width of Rectangular room = 9.6 m
<u>So We have to find the area of the room.</u>
We know :
<h3>Area of Rectangle = Length times Width </h3>
<u>Area of Rectangular room = Length of Rectangular room × Width of Rectangular room </u>
Area of Rectangular room = 6.9 m × 9.6 m
Area of Rectangular room = 6.9 m × 9.6 m Area of Rectangular room = 66.24 m²
Therefore, Required area of the room is 66.24 m².