Answer:
- an = 2·(4/5)^(n-1)
- 2, 8/5, 32/25, 128/125
Step-by-step explanation:
The sum of an infinite geometric series is ...
S = a1/(1 -r)
where r is the common ratio. The sum will only exist if |r| < 1.
The problem statement tells us S = 10 and a1 = 2, so we have ...
10 = 2/(1 -r)
r = 1 -2/10 = 4/5
So the n-th term of the series is ...
an = a1·r^(n-1)
an = 2·(4/5)^(n-1)
For values of n = 1 to 4, the terms are ...
2, 8/5, 32/25, 128/125
Answer:
k=−0.8
Step-by-step explanation:
Start with the equation: 0.2(3k+1)=-0.4-(-0.2-0.1K)
Use distributive property on each side of the equation. For the left side, distribute 0.2 into 3k and 1, and for the right side, distribute -1 into -0.2 and -0.1k. (We use a -1 because the negative sign on the outside of the parenthesis is equivalent to -1)
(0.2)(3k) + (0.2)(1) = 0.6k + 0.2
(-1)(-0.2) + (-1)(-0.1k) = 0.2 + 0.1k
New equation: 0.6k + 0.2 = -0.4 + 0.2 + 0.1k
Now we can combine like terms on the right side. (-0.4 and 0.2)
0.6k + 0.2 = 0.1k - 0.2
Now to get rid of k on one side, we can subtract 0.1k from the right side.
(0.6k - 0.1k) + 0.2 = (0.1k - 0.1k) - 0.2
0.5k + 0.2 = -0.2
Now we need to get 0.5k by itself, so we'll subtract the 0.2 on both sides.
0.5k + (0.2 - 0.2) = (-0.2 - 0.2)
0.5k = -0.4
To get k by itself, we must divide both sides by 0.5.
(0.5k / 0.5) = (-0.4 / 0.5)
k = -0.8
-x+4
because you simply go ahead and distribute the negative.
hope this helped.
64 divided by 8 is 8. 8 pints fit in one gallon. She carries 2 gallon jugs, so that's 16 pints. So each day she carries 4 2 gallon jugs to meet her catering business demands.
Answer:
7 employees
Step-by-step explanation:
Given that 10% are temporary .
So number of temporary employees will be 10% of 70 employees = 7employees ( Answer)
