Answer:
Theorem : Opposite sides of a parallelogram are congruent or equal.
Let us suppose a parallelogram ABCD.
Given:AB\parallel CD and BC\parallel AD (According to the definition of parallelogram)
We have to prove that: AB is congruent to CD and BC is congruent to AD.
Prove: let us take two triangles, \bigtriangleup ACD and\bigtriangleup ABC
In these two triangles, \angle1=\angle2 { By the definition of alternative interior angles}
Similarly, \angle4=\angle3
And, AC=AC (common segment)
By ASA, \bigtriangleup ACD \cong \bigtriangleup ABC
thus By the property of congruent triangle, we can say that corresponding sides of \bigtriangleup ACD and \bigtriangleup ABC are also congruent.
Thus, AB is congruent to CD and BC is congruent to AD.
Take away 57 from the total to make the two numbers equal:
191 - 57 = 134
Divide by 2 to find the smaller number:
134 ÷ 2 = 67
Add 57 back to the number to find the bigger number:
67 + 57 = 124
Answer: The smaller number is 67 and the bigger number is 124
A is the answer you are looking for.
Answer:
B
Step-by-step explanation:
Answer:
(a) Normal model
Step-by-step explanation:
Given
Solving (a): The distribution type
The sample follows a normal model
Solving (b): The mean
This is calculated as:
So, we have:
Express as decimal
Solving (c): The standard deviation
This is calculated as:
So, we have:
Express as decimals