If 2x-3y=10. and xy=16 find the value of8x³-27y³
1 answer:
Answer:
8x³-27y³=3880
Step-by-step explanation:
2x-3y=10
xy=16
8x³-27y³=?
as we know that
(a-b)³=a³-b³-3ab(a-b)
now we substitue the formula according to our question
(2x-3y)³=(2x)³-(3y)³-3(2x)(3y)(2x-3y)
(10)³=8x³-27y³-18(16)(10)
1000=8x³-27y³-2880
1000+2880=8x³-27y³
3880=8x³-27y³
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