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3 years ago

If 2x-3y=10. and xy=16 find the value of8x³-27y³

Mathematics

1 answer:

andrew11 [14]3 years ago

7 0

Answer:

8x³-27y³=3880

Step-by-step explanation:

2x-3y=10

xy=16

8x³-27y³=?

as we know that

(a-b)³=a³-b³-3ab(a-b)

now we substitue the formula according to our question

(2x-3y)³=(2x)³-(3y)³-3(2x)(3y)(2x-3y)

(10)³=8x³-27y³-18(16)(10)

1000=8x³-27y³-2880

1000+2880=8x³-27y³

3880=8x³-27y³

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2 years ago

Given csc(A) = 60/16 and that angle A is in Quadrant I, find the exact value of sec A in simplest radical form using a rational

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Answer:

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3 years ago

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3 years ago

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Maurinko [17]

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6 0

2 years ago

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If sin ? = 12 over 37, use the pythagorean identity to find cos ?. cos ? = ± 35 over 37 cos ? = ± 23 over 37 cos ? = ± 35 over 1

kotegsom [21]

If sin x = 12/37, we have to find cos x.
The identity:
sin² x + cos² x = 1
( 12/37)² + cos² x = 1
144 / 1369 + cos² x = 1
cos² x = 1 - 144/1369
cos² x = 1369/1369 - 144/1369
cos² x = 1225 / 1369
cos x = +/- √ 1225/1369 = +/- 35/37
Answer:
A ) cos ? = +/- 35 over 37

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2 years ago

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