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kiruha [24]
4 years ago
9

A football player weighed 170 2/3 pounds in May. During the summer, he gained 25 5/12 pounds. During the first week of fall prac

tice, he lost 10 1/4 pounds, and during the second week he lost another 3 1/2 pounds. How much did he weigh at that point?
A: 182 1/3 lb
B: 181 1/2 lb
C: 182 5/12 lb
D: 183 2/3 lb

Help please?

Mathematics
2 answers:
12345 [234]4 years ago
8 0

Answer:

;D it's :D

hope this helps

pochemuha4 years ago
4 0

Answer:

182 1/3 lbs

MAY:  weight = 170 2/3

Summer: gained 25 5/12

New weight : 170 2/3 + 25 5/12  

Get a common denominator of 12

170 2/3 *4/4  + 25 5/12

170 8/12 + 25 5/12 = 195 13/12

The he lost 10 1/4 during the first week of fall practice

195 13/12 - 10 1/4

We need to get a common denominator of 12

195 13/12 - 10 1/4*3/3

195 13/12 - 10 3/12

185 10/12

The he lost another 3 1/2 pound during the second week

185 10/12 - 3 1/2

We need to get a common denominator of 12

185 10/12 - 3 1/2 * 6/6

185 10/12 - 3 6/12

182 4/12

Simplify the fraction

182 1/3 lbs

Hope this helps!

have a great day! :))))))

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In order to solve this problem, you need to use a geometric series:
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n = number of terms = 5

Therefore,
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Answer:

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108 ÷ 9 x (-12) ÷ 6 - (100 ÷ 5)

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Answer:

Step-by-step explanation:

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