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nlexa [21]
3 years ago
10

I need help asap i dont understand it at all and its countng agianst my grade

Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
7 0

Answer:

dang i dont understand either

Step-by-step explanation:

Ludmilka [50]3 years ago
4 0

Answer:

1 = 1.3

3 = 3.3

0 = 40

Step-by-step explanation:

i tried my best, hope u get a good score !

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Ainat [17]

Happy Thanksgiving b I'm pretty sure

3 0
3 years ago
Find the standard deviation of the data, 12, 19, 9.
jek_recluse [69]

Answer:

4.19

Step-by-step explanation:

Find the mean:

\text{Mean}=\frac{12+19+9}{3}=\frac{40}{3}

Find the standard deviation:

\text{Standard Deviation}=\sqrt{\frac{(12-\frac{40}{3})^2+(19-\frac{40}{3})^2+(9-\frac{40}{3})^2}{3}}=\sqrt{\frac{158}{9}}\approx4.19

4 0
3 years ago
Solution to system of equations
Rufina [12.5K]

Answer: In general, a solution of a system in two variables is an ordered pair that makes BOTH equations true. In other words, it is where the two graphs intersect, what they have in common. So if an ordered pair is a solution to one equation, but not the other, then it is NOT a solution to the system

6 0
3 years ago
Arrange0.2,¼,30%,10%in ascending and descending order​
BARSIC [14]

Answer:

Ascending- 10%, 0.2, 1/4, 30%

Descending- 30%, 1/4, 0.2, 10%

Step-by-step explanation:

0.2 = 2/10 = 4/20

1/4 = 5/20

30% = 30/100 = 6/20

10% = 10/100 = 2/20

Ascending

-2/20, 4/20, 5/20, 6/20

- 10%, 0.2, 1/4, 30%

Descending

- 6/20, 5/20, 4/20, 2/20

- 30%, 1/4, 0.2, 10%

7 0
3 years ago
The sum of the first n terms of an arithmetic series is n/2(3n-5). If the second and fourth terms of the arithmetic series are t
sergiy2304 [10]

Let <em>a</em> be the first term in the arithmetic sequence. Since it's arithmetic, consecutive terms in the sequence differ by a constant <em>d</em>, so the sequence is

<em>a</em>, <em>a</em> + <em>d</em>, <em>a</em> + 2<em>d</em>, <em>a</em> + 3<em>d</em>, …

with the <em>n</em>-th term, <em>a</em> + (<em>n</em> - 1)<em>d</em>.

The sum of the first <em>n</em> terms of this sequence is given:

a + (a+d) + (a+2d) + \cdots + (a+(n-1)d) = \dfrac{n(3n-5)}2

We can simplify the left side as

\displaystyle \sum_{i=1}^n (a+(i-1)d) = (a-d)\sum_{i=1}^n1 + d\sum_{i=1}^ni = an+\dfrac{dn(n-1)}2

so that

an+\dfrac{dn(n-1)}2 = \dfrac{n(3n-5)}2

or

a+\dfrac{d(n-1)}2 = \dfrac{3n-5}2

Let <em>b</em> be the first term in the geometric sequence. Consecutive terms in this sequence are scaled by a fixed factor <em>r</em>, so the sequence is

<em>b</em>, <em>br</em>, <em>br</em> ², <em>br</em> ³, …

with <em>n</em>-th term <em>br</em> ⁿ⁻¹.

The second arithmetic term is equal to the second geometric term, and the fourth arithmetic term is equal to the third geometric term, so

\begin{cases}a+d = br \\\\ a+3d = br^2\end{cases}

and it follows that

\dfrac{br^2}{br} = r = \dfrac{a+3d}{a+d}

From the earlier result, we then have

n=7 \implies a+\dfrac{d(7-1)}2 = a+3d = \dfrac{3\cdot7-5}2 = 8

and

n=2 \implies a+\dfrac{d(2-1)}2 = a+d = \dfrac{3\cdot2-5}2 = \dfrac12

so that

r = \dfrac8{\frac12} = 16

and since the second arithmetic and geometric terms are both 1/2, this means that

br=16b=\dfrac12 \implies b = \dfrac1{32}

The sum of the first 11 terms of the geometric sequence is

<em>S</em> = <em>b</em> + <em>br</em> + <em>br</em> ² + … + <em>br</em> ¹⁰

Multiply both sides by <em>r</em> :

<em>rS</em> = <em>br</em> + <em>br</em> ² + <em>br</em> ³ + … + <em>br</em> ¹¹

Subtract this from <em>S</em>, then solve for <em>S</em> :

<em>S</em> - <em>rS</em> = <em>b</em> - <em>br</em> ¹¹

(1 - <em>r</em> ) <em>S</em> = <em>b</em> (1 - <em>r</em> ¹¹)

<em>S</em> = <em>b</em> (1 - <em>r</em> ¹¹) / (1 - <em>r</em> )

Plug in <em>b</em> = 1/32 and <em>r</em> = 1/2 to get the sum :

S = \dfrac1{32}\cdot\dfrac{1-\dfrac1{2^{11}}}{1-\dfrac12} = \boxed{\dfrac{2047}{32768}}

6 0
3 years ago
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