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3 years ago

Which of the following probabilities is the greatest for a standard normal distribution?

Mathematics

1 answer:

MissTica3 years ago

7 0

I think is p(0.5 5731.5)

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NARA [144]

Answer:

5.90551

Step-by-step explanation:

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3 years ago

Find the value of x to the nearest degree.

Vinvika [58]

Answer: 77°

Step-by-step explanation:

In relation to ∠X, 3 is the adjacent side and 13 is the opposite side.

$tan\ \theta=\dfrac{opposite}{adjacent}\\\\tan\ x=\dfrac{13}{3}\\\\x = tan^{-1}\bigg(\dfrac{13}{3}\bigg)\\\\.\ =77$

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4 years ago

Factor the expression completely. 63x – 9

liraira [26]

Answer:

The answer is 9(7x – 1).

Step-by-step explanation:

63x – 9

3 × 3 × 7 × x – 3 × 3

9(7x – 1)

Thus, The answer is 9(7x – 1).

-TheUnknownScientist 72

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3 years ago

Name: 1. Graph a) y = 3x

oksian1 [2.3K]

This is how it looks on a graph.

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3 years ago

Find the distance between the two given points. O(-3,-2) and P(-3,4)

aliina [53]

Answer:

$\boxed {\boxed {\sf d= 6}}$

Step-by-step explanation:

Distance can be found using this formula:

$d=\sqrt {(x_2-x_1)^2+(y_2-y_1)^2$

Where (x₁, y₁) and (x₂, y₂) are the points.

We are given the points O (-3, -2) and P(-3,4). Therefore,

$x_1= -3 \\y_1= -2 \\x_2= -3 \\y_2=4$

Substitute the values into the formula.

$d=\sqrt {(-3--3)^2+(4--2)^2$

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition and Subtraction.

Solve inside the parentheses first.

(-3--3)= -3+3=0
(4--2)= 4+2=6

$d= \sqrt {(0)^2+ (6)^2}$

Solve the exponents.

(0)²= 0*0=0
(6)²= 6*6=36

$d=\sqrt {0+36$

Add.

$d= \sqrt {36$

Take the square root.

$d=6$

The distance is 6.

3 0

3 years ago