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2 years ago

If |x|+10=1, then what does x equal

Mathematics

2 answers:

Pie2 years ago

6 0

Answer; there is literally no solution. it has to be a negative number.

QveST [7]2 years ago

5 0

There’s no solution

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The quadratic function below has an axis of symmetry through x = -4; a vertex at (-4, -9) and zeroes at x = -7 and x = 0.

Pavlova-9 [17]

Answer:

True

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (- 4, - 9), thus

y = a(x + 4)² - 9

To find a substitute the coordinates of the zero (- 7, 0) into the equation.

0 = a(- 7 + 4)² - 9, that is

0 = 9a - 9 ( add 9 to both sides )

9a = 9 ( divide both sides by 9 )

a = 1, thus

y = (x + 4)² - 9 ← expand factor using FOIL

y = x² + 8x + 16 - 9

y = x² + 8x + 7

4 0

2 years ago

Given that y is directly proportional to x^2 and that y=2 when x=3 find the value of y when x=6

Sergio039 [100]

Answer:y=4/3

y is directly proportional to x^2 is written as

$y \alpha {x}^{2}$ introducing a constant,

y=kx^2

but from the question, when y=2 , x=3 . putting it in the formula to get the value of k

$2 = {3}^{2} \times k$

2=9k . dividing through by 9 to get the value of k

 $\frac{2}{9} = \frac{9k}{9}$ 

 $k = \frac{2}{9}$ 

putting it in the general expression

 $y = \frac{2}{9} x$ 

the value of y when x=6

 $y = \frac{2}{9} \times 6$ 

 $y = \frac{4}{3}$ 

therefore the value of y when x=6 is

4/3

3 0

3 years ago

Now consider just the second sentence of the multistep word problem. Sentence 2: If four times the brother's age is subtracted f

Natalka [10]

Answer:

4b - 3s = 40

4b = 40 + 3s

b = 40 - 3s/4

4b - 3s = 40

4b - 40 =3s

4b - 40 /3 = s

8 0

3 years ago

Express the equation in rectangular form a) r = 2sin(2Θ) b) r = 4cos(3Θ)

Dafna11 [192]

Answer:

a. sqrt(x^2+y^2) * (x^2+y^2) = 4xy

b. (x^2+y^2)^2 = 4x{ (x^2 - 3 y^2}

Step-by-step explanation:

a) r = 2sin(2Θ)

r* = 2 sin 2 theta

We know sin 2theta = 2 sin theta cos theta

r = 2 * 2 sin theta cos theta

sin theta = y/r and cos theta = x/r

r = 4 y/r * x/r

r = 4xy / r^2

Multiply each side by r^2

r^3 = 4xy

r * r^2 = 4xy

We know r = sqrt(x^2+y^2) and r^2 = (x^2+y^2)

sqrt(x^2+y^2) * (x^2+y^2) = 4xy

b) r = 4cos(3Θ)

we know that cos 3 theta = cos^3(theta) - 3 sin^2(theta) cos(theta)

r = 4 *cos^3(theta) - 3 sin^2(theta) cos(theta)

Factor out a cos theta

r = 4 *cos(theta){ cos^2 (theta) - 3 sin^2(theta) }

We know that sin theta = y/r and cos theta = x/r

r = 4 (x/r) { (x/r)^2 - 3 (y/r)^2}

r = 4 *(x/r) { (x^2/r^2 - 3 y^2/r^2}

Multiply by r

r^2 = 4x { (x^2/r^2 - 3 y^2/r^2}

Multiply by r^2

r^2 *r^2 = 4x { (x^2 - 3 y^2}

r^4 = 4x{ (x^2 - 3 y^2}

We know r^2 = (x^2+y^2)

(x^2+y^2)^2 = 4x{ (x^2 - 3 y^2}

5 0

3 years ago

What is the word pharse for y/5

Vitek1552 [10]

I'm pretty sure it's y divided by 5 because the fraction bar means divided by

3 0

3 years ago