Let's begin by listing out the information given to us:
There are four students: n = 4
Number of students to be selected: r = 2
To calculate the combination of 2 students to be chosen, we use:

Therefore, there 12 possible combinations from these
Buzz has 4 friends and Brock has 6.
The reason being is that Buzz has to have two less friend than Brock has, and yet still both have to add up to ten.
Is there any more to this question? Because-5 doesn’t belong anywhere
This would be 525 / 0.70 = $750 Answer