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NemiM [27]
2 years ago
13

list 5 examples and application where geometric sequences occur in everyday life.justify your answer are geometric sequences ​

Mathematics
1 answer:
lbvjy [14]2 years ago
7 0
A ball bouncing is an example of a finite geometric sequence. Each time the ball bounces it's height gets cut down by half. If the ball's first height is 4 feet, the next time it bounces it's highest bounce will be at 2 feet, then 1, then 6 inches and so on, until the ball stops bouncing.
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i need help with my math :( im horrable with it i cant do divideing fractions nor multiply and i dont know most of my multiples
vladimir1956 [14]

Step-by-step explanation:

To multiply the fractions, like

\frac{1}{4}  \times  \frac{1}{9}

Multiply the top,

then multiply the bottom.

\frac{1}{4}  \times  \frac{1}{9}  =  \frac{1 \times 1}{4 \times 9}  =  \frac{1}{36}

Try to use a calculator if you aren't arithmetic heavy, but I suggest you to try to remember them because they are going to be helpful for courses like Algebra, Calculus, Statistics, etc.

To divide fractions, like

\frac{ \frac{1}{5} }{ \frac{1}{8} }

You take the top number,

\frac{1}{5}

Then you flip the bottom number,

\frac{8}{1}

Then multiply the two

\frac{1}{5}  \times  \frac{8}{1}  =  \frac{8}{5}

And that is your answer. Comment if you need more clarification

6 0
1 year ago
Plz answer me will mark as brainliest read full question
Musya8 [376]

Answer:83 -->17-->103-->43-->7-->1

Have a good day

6 0
3 years ago
Sugar was traditionally produced and sold as sugarloaves, which are cones of sugar wrapped in paper. Find the total surface area
Zolol [24]

Answer:

A = 326,73 cm²

Step-by-step explanation:

The area of a circular cone is area of the base (A₁ ) plus area lateral ( area of a circular sector of radius the slant height )

Then we proceed to calculate the area of the base A₁

diameter of circular base is 8 cm then the radius is 4 cm and the area is:

A₁ = π*r²  =  3,14* (4)²

A₁ = 3,1416*16   =  50,2656 cm²

Now Lateral area of the cone (A₂) is equal to the area of a circular sector with radius the slant height. We will calculate it, taken into account that this circular sector is part of a circle of radius the slant height.

Between the area of circular sector with radius the slant height and the area of the circle with the same radius there is a linear relation. That is we can calculate area of a circular sector by rule of three as follows:

The length of the circular sector is the length of the circle of the base of the cone, that is:

L = 2*π*(4)

L = 2*3,1416*4

L = 25,1328 cm

Then we have a circular sector of length 25,1328 cm

The area of the circle of radius 22 cm is:

A(c)  = π*(22)²     ⇒   A(c)  = 1520,5344 cm²

And the length of this circle is:

L(c)  =  2*π*(22)     ⇒   138,2304 cm

Then we apply a rule of three

For a length of      138,2304 cm  ⇒⇒⇒  (area)  1520,5344 cm²

Then for a length of  25,1328 cm   ⇒⇒⇒(area)   A₂ (??)

Therefore:

A₂ =  (25,1328)*1520,5344)/ 138,2304

A₂ = 276,4608 cm²

Then total area of the cone is:

A = A₁  +  A₂

A =  50,2656  +276,4608

A  = 326,7264 cm²

Round answer  A = 326,73 cm²

8 0
3 years ago
Read 2 more answers
Alexus is ordering a large pizza for lunch. She has $15 dollars in all. A large pizza costs $9 and
exis [7]

Step-by-step explanation:

It would be

9+6 because 0.50 is a dollar so if u multiply by 6 and add the 9 the equation would be 9+6.......

don't forget get to rate me thx:)

4 0
3 years ago
The General Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hours
DerKrebs [107]

Answer:

Yes, we can conclude that the population standard deviation of TV watching times for teenagers is less than 2.66

Step-by-step explanation:

H0 : σ² = 2.66²

H1 : σ² < 2.66²

X²c = (n - 1)*s² ÷ σ²

sample size, n = 40

Sample standard deviation, s = 1.9

X²c = ((40 - 1) * 1.9²) ÷ 2.66²

X²c = 140.79 ÷ 7.0756

X²c = 19.897

Using a confidence level of 95%

Degree of freedom, df = n - 1 ; df = 40 - 1 = 39

The critical value using the chi distribution table is 25.6954

Comparing the test statistic with the critical value :

19.897 < 25.6954

Test statistic < Critical value ; Reject the Null

Hence, we can conclude that the population standard deviation of TV watching times for teenagers is less than 2.66

8 0
3 years ago
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