Question

Kiran, Mai, and Tyler went to their school carnival. They all won chips that they could exchange for prizes. Kiran won 2/3 as many chips as Jada, Mai won 4 times as many chips as Kiran. Tyler won half as many chips as Mai. If Jada won 42 chips, how many chips did Tyler, Kiran, and Mai each win?

Answer 1

Answer:

k = 28

m = 112

t = 56

Step-by-step explanation:

From the question, the following equations can be derived

Kiran's chips (k) = 2/3 x J

Mai (M) = 4 x k

Tyler = 1/2 x M

If Jada won 42 chips, Kiran's chips (k) = 2/3 x 42 = 28

Mai = 4 x 28 = 112

Tyler = 1/2 x 112 = 56