Answer:
Step-by-step explanation:
<u>Given the sequence:</u>
The first term is 10 and the common difference is -5
<u>The recursive formula for the given sequence is:</u>
Answer:
160 not interested and 144*
Step-by-step explanation:
* is the degree sign like the little o
Answer:
(8,2)
Step-by-step explanation:
The solution is where the two graphs intersect.
The two graphs intersect at x=8 and y=2
(8,2)
Use the trig identity
2*sin(A)*cos(A) = sin(2*A)
to get
sin(A)*cos(A) = (1/2)*sin(2*A)
So to find the max of sin(A)*cos(A), we can find the max of (1/2)*sin(2*A)
It turns out that sin(x) maxes out at 1 where x can be any expression you want. In this case, x = 2*A.
So (1/2)*sin(2*A) maxes out at (1/2)*1 = 1/2 = 0.5
The greatest value of sin(A)*cos(A) is 1/2 = 0.5
In degrees: 3π/4 radians = 135°
Angle of x=135° is in the 2nd Quadrant and has negative cos x values and positive sin x values.
cos 135° = cos ( 90° + 45°)= - sin 45° =

sin 135° = sin ( 90° + 45° ) = cos 45° =

. You can also see the graph in the attachment.