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lara [203]
3 years ago
12

You plan to set up an endowment at your alma mater that will fund $209,000 of scholarships each year indefinitely. If the princi

pal (the amount you donate) can be invested at 5.0 percent, compounded annually, how much do you need to donate to the university today, so that the first scholarships can be awarded beginning one year from now
Mathematics
1 answer:
Leto [7]3 years ago
6 0

Answer:

$199,047.62

Step-by-step explanation:

PV = X(1+i)^nm

X=$209000

i=5% = 0.05

n=1

m=1

Pv=$209000(1+0.05)^-1x1

Pv=$209000(1.05)^-1

Pv=$209000(1/1.05)

Pv=$209000/1.05

Pv=$199,047.62

$199,047.62 is needed to be donated for investment at 5.0% compounded annually rate for a year so as to get $209,000 at end of the year for the purpose of funding the scholarship.

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6. Consider the polynomial p(x) = x^2 + kr^2 +x+6. Find a value of k so that x+1 is a factor of P. Find all the zeros of P.​
Nikitich [7]

If <em>x</em> + 1 is a factor of <em>p(x)</em> = <em>x</em>³ + <em>k</em> <em>x</em>² + <em>x</em> + 6, then by the remainder theorem, we have

<em>p</em> (-1) = (-1)³ + <em>k</em> (-1)² + (-1) + 6 = 0   →   <em>k</em> = -4

So we have

<em>p(x)</em> = <em>x</em>³ - 4<em>x</em>² + <em>x</em> + 6

Dividing <em>p(x)</em> by <em>x</em> + 1 (using whatever method you prefer) gives

<em>p(x)</em> / (<em>x</em> + 1) = <em>x</em>² - 5<em>x</em> + 6

Synthetic division, for instance, might go like this:

-1   |   1    -4     1     6

...   |         -1    5    -6

----------------------------

...   |   1    -5    6     0

Next, we have

<em>x</em>² - 5<em>x</em> + 6 = (<em>x</em> - 3) (<em>x</em> - 2)

so that, in addition to <em>x</em> = -1, the other two zeros of <em>p(x)</em> are <em>x</em> = 3 and <em>x</em> = 2

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3 years ago
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Answer:

Area of the circle=πr²

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4 0
3 years ago
When a constant force is applied to an object, the acceleration of the object varies inversely with its mass. When a certain con
marusya05 [52]

Answer: The mass of the object is 10 kg

Step-by-step explanation:

According to Newton's second law of motion, the force F applied to an object with mass m is directly proportional to its acceleration a:

F=ma (1)

If we isolate a:

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Now, we are given the following data to calculate a constant force using (1):

m_{1}=4 kg

a_{1}=5 m/s^{2}

F=m_{1}a_{1} (3)

F=(4 kg)(5 m/s^{2) (4)

F=20 N (5)

If we apply this same force calulated in (4) in another object with an acceleration of a_{2}=2 m/s^{2}, its mass m_{2} will be:

F=m_{2}a_{2} (6)

20 N=m_{2}2 m/s^{2} (7)

Finding  m_{2}:

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3 years ago
Tristan has 45 apples and 20 pears that he is putting into gift baskets. Each basket will have the same number of apples and pea
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