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Marina CMI [18]
3 years ago
11

zoey made 5 1/2 cups of trail mix for a camping trip. she wants to divide the trail mix into 3/4 cup servings. ten people are go

ing on the camping trip, cam zoey make enough 3/4 cup servings so that each person on the trip has one serving. plz i need these answers asap on the pic. # 13, a., b., and c.

Mathematics
2 answers:
ANEK [815]3 years ago
7 0
10 * 3/4 = 30/4 = 15/2 = 7 1/2
7 1/2 > 5 1/2
a ) Zoey can`t make enough 3/4 cup servings.
b ) 5 1/2 : 10 = 11/2 : 10 = 11/2 * 1/10 = <span>11/20 cup servings
c ) She </span><span>will need 7 1/2 -</span> 5 1/2 = 2 cups of trail mix more.
Andreas93 [3]3 years ago
6 0
A.) Number of 3/4 cup servings in 5 1/2 cups = 5 1/2 / 3/4 = 11/2 / 3/4 = 11/2 x 4/3 = 44/6 = 7 1/3
Therefore, Zoey did not make enough 3/4 cup serving to go round everybody.

b.) For, every one to have a serving, we have 5 1/2 cups which we want to go round ten people, so each person should get 5 1/2 / 10 = 11/2 / 10 = 11/2 x 1/10 = 11/20.
So the serving should be 11/20 cup for every one to get serving.

c.) If she uses the 3/4 cup serving, then she will need 3/4 x 10 = 30/4 = 7 1/2 cups altogether.
Therefore, she will need to make extra 7 1/2 - 5 1/2 = 2 cups of trail mix.
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Prove set equality by showing that for any element x, x \in (A \backslash (B \cap C)) if and only if x \in ((A \backslash B) \cup (A \backslash C)).

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Proof for [x \in (A \backslash (B \cap C))] \implies [x \in ((A \backslash B) \cup (A \backslash C))] for any element x:

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Therefore, x \in ((A \backslash B) \cup (A \backslash C)) as required.

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Assume that x \in ((A \backslash B) \cup (A \backslash C)). Thus, either x \in (A \backslash B) or x \in (A \backslash C) (or both.)

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Either way, x \in A \backslash (B \cap C).

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kirill [66]
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This is due to the fact that 10% is 0.75
You can get 10% by dividing the number by 10.
10% doubled to get 20% is £1.50
7.50 minus the 20% off, 1.50, would be £5.


5 0
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