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stira [4]
3 years ago
13

If f(x) = 2^x + 4 and g(x) = x^2 – 4 what is the value of f(5) +g(-3)

Mathematics
1 answer:
Anon25 [30]3 years ago
8 0

f(5)=2^5+4

f(5)=32+4=36

g(-3)=(-3)^2-4

=9-4

=5

f(5)+g(-3)=36+5

=41

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(-13xy+2y)+(2x-5xy-15y)
Arturiano [62]

Answer:-18xy+2x-13y

Step-by-step explanation: combine like terms

3 0
2 years ago
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Write an equation in point-slope form of the line that passes through the point 4,-1and has slope of -5
Basile [38]

Answer:

y=-5+19

Step-by-step explanation:

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

To start, you know what m is; it's just the slope, which you said was -5. So you can right away fill in the equation for a line somewhat to read:

y=-5x+b.

Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:

(4,-1). When x of the line is 4, y of the line must be -1.

Because you said the line passes through this point, right?

Now, look at our line's equation so far: . b is what we want, the -5 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (4,-1).

So, why not plug in for x the number 4 and for y the number -1? This will allow us to solve for b for the particular line that passes through the point you gave!.

(4,-1). y=mx+b or -1=-5 × 4+b, or solving for b: b=-1-(-5)(4). b=19.

6 0
3 years ago
There are 8 fewer tigers than lions at the zoo. There are 8 tigers at the zoo. How many lions does the zoo have?
Aleks04 [339]
Sixteen because if there are eight less tigers than lions at a zoo, then that means you add 8 to get the number of lions

8 0
3 years ago
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What is the area of each section of the poster?<br><br> On no. 10.
rosijanka [135]
I hope this helps you


2 (x+x+x+x+x+24+24)=120


4x+48=60


x=3


Area =2x.24


Area =2.3.24


Area =144
6 0
3 years ago
a square stained window is divided into four congurent traiangular sections by iron edging to represent seasons of the year. Eac
Norma-Jean [14]

Answer:

Total length of iron needed to make the square frame and two diagonals =  43.44 in (Approx)

Step-by-step explanation:

Given:

Length of diagonal = 9 in

Find:

Total length of iron needed to make the square frame and two diagonals.

Computation:

Area of square = 1/2(diagonal)²

Area of square = 1/2(9)²

Area of square = 40.5 in²

Area of square = Side × Side

40.5 in² = Side × Side

Side = 6.36 (approx)

Total length of iron needed to make the square frame and two diagonals = Permeter of square + (2 × diagonal)

⇒ (4 × 6.36) + (2 × 9)

⇒ (25.44) + (18)

⇒ 43.44 in

Total length of iron needed to make the square frame and two diagonals =  43.44 in (Approx)

4 0
3 years ago
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