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stira [4]
3 years ago
13

If f(x) = 2^x + 4 and g(x) = x^2 – 4 what is the value of f(5) +g(-3)

Mathematics
1 answer:
Anon25 [30]3 years ago
8 0

f(5)=2^5+4

f(5)=32+4=36

g(-3)=(-3)^2-4

=9-4

=5

f(5)+g(-3)=36+5

=41

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Find the values of a and b such that
Varvara68 [4.7K]

Answer:

a = 1.5

b = 1.75

Step-by-step explanation:

First, we need to solve (x+a)^2 and replace the result in the initial equation as:

x^2+3x+4=(x+a)^2+b\\x^2+3x+4=x^2+2ax+a^2+b

Then, this equality apply only if the coefficient of x is equal in both sides and the constant is equal in both sides.

It means that we have two equations:

3x=2ax\\4=a^2+b

So, using the first equation and solving for a, we get:

3x=2ax\\3=2a\\a=\frac{3}{2}=1.5

Finally, replacing the value of a in the second equation and solving for b, we get:

4=a^2+b\\4=1.5^2+b\\b=4-1.5^2\\b=4-2.25\\b=1.75

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3 years ago
Find a value for y for which the expression (1-y)(3-y)(6-y) has each given value
erik [133]

\\ \tt\Rrightarrow (1-y)(3-y)(6-y)=-70

\\ \tt\Rrightarrow -y(1+1)(3+1)(6+1)=-70

\\ \tt\Rrightarrow y(2)(4)(7)=70

\\ \tt\Rrightarrow y(56)=70

\\ \tt\Rrightarrow y=\dfrac{70}{56}

\\ \tt\Rrightarrow y=\dfrac{5}{4}

#2

\\ \tt\Rrightarrow (1-y)(3-y)(6-y)=120

\\ \tt\Rrightarrow -y(1+1)(3+1)(6+1)=120

\\ \tt\Rrightarrow -y(2)(4)(7)=120

\\ \tt\Rrightarrow 56y=-120

\\ \tt\Rrightarrow y=\dfrac{-120}{56}

\\ \tt\Rrightarrow y=\dfrac{-15}{7}

7 0
2 years ago
Read 2 more answers
What is the result of isolating y2 in the equation below?
lyudmila [28]
STEP-BY-STEP SOLUTION:

( x + 4 )^2 + y^2 = 22

x^2 + 2 × x × 4 + 4^2 + y^2 = 22

x^2 + 8x + 16 + y^2 = 22

y^2 = 22 - x^2 - 8x - 16

y^2 = - x^2 - 8x + 6

FINAL ANSWER:

Therefore, the answer is:

D. y^2 = - x^2 - 8x + 6

Please mark as brainliest if you found this helpful! :)
Thank you <3
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3 years ago
Question 1 (Multiple Choice Worth 4 points)
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Answer:

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3 years ago
If a club charges dues of $200 a year, it will have 50 members. For each $5 it raises its dues, it loses a member. USE AN EQUATI
Vikentia [17]

Answer:

The value is      y  =  \$ 225

Step-by-step explanation:

From the question we are told that

   The amount charge per year is  k  =  \$ 200

   The  number of members it will have at this amount is  n  =  50

   The amount amount increase that will lead to the loss of a single member is   z =  \$ 5

        Generally the total amount the club would obtain from  its members is mathematically represented as

      I  =  Amount \  due\ paid *  Number \  of members

Now let x denote the number of member lost

Hence

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=>    I  =  (200 + 5x) (50-x )

=>  I  = 10000+50x-5x^2

Thus the number of members that be removed to  give the maximum  income from dues is obtained by differentiating the above equation and equating it to zero

           \frac{dI}{dx}  =  50-10x

=>         x   =  5

So from  I  =  (200 + 5x) (50-x ) we have

          I  =  (200 + 5 (5)) (50-5 )

           I  = \$ 10125

So the amount the club should charge is    

         y  =  \frac{10125}{50 - 5}

         y  =  \$ 225

         

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