<span>3
classmates shares 2 granola bars.
IF they shared it equally, how much will each of them get?
=> 3 classmate = 2 available granola
Let’s divide the 2 granola in each of them
=> 2 /3
=> 0.67
Thus, each of them is expected to receive approximately 0.67 granola each
=> Unit rate = 0.67 granola / person. </span>
The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus,
1.22 a = 12.0 - T (eqn 1)
and for the 20.0 N block:
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction)
2.04 a = T - 6.5 (eqn 2)
[eqn 1] + [eqn 2] → 3.26 a = 5.5
a = 1.69 m/s²
Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5
T = 9.95 N
Now want the resultant force acting on the 20.0 N block:
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N
<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>
75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>
Answer:
5th term
Step-by-step explanation:
x^2 +3 = 28
Subtract 3 from each side
x^2+3-3 =28-3
x^2 = 25
Take the square root of each side
sqrt(x^2) = sqrt(25)
x = 5
(x could be -5, but there are not usually negative terms in a sequence)
Answer:
If two expressions are equal to each other, and you add the same value to both sides of the equation, the equation will remain equal. When you solve an equation, you find the value of the variable that makes the equation true. In order to solve the equation, you isolate the variable.
PEMDAS tells us to use multiplication and division before addition and subtraction.
<u>-5(8) </u>÷ 10 - <u>14 ÷ 7</u> - <u>(-2)(3)</u>
<u> -40 ÷ 10</u> - 2 - -6
<u>-4 - 2 </u> + 6 <em>two negatives make a positive so - - 6 = + 6</em>
<u> -6 +6</u>
0
Answer: 0
