Question

Use the quadratic formula to find both solutions to the quadratic equation given below 3x^2-x+6=0

Answer 1

Hello from MrBillDoesMath!

Answer:

Choice E and F

Discussion:

From the quadratic formula with a = 3, b = -1, and c = 6

x =  ( -b +\- sqrt(b^2 - 4ac)  ) / (2a)       => substitute in a,b,c from above

x = ( -(-1) +\- sqrt((-1)^2 - 4(3)(6)) / (2*3)  => discriminant = 1 - 72 = -71)

x = ( 1 +\- sqrt(-71))/ 6

which are choices E and F

Thank you,

MrB

Answer 2

Answer:

Choices E and F are the answers.

Step-by-step explanation:

We have given a quadratic equation.

3x²-x+6 = 0

We have to solve given equation by quadratic formula.

x = (-b±√b²-4ac) / 2a is quadratic formula to solve this.

In given equation, a = 3 , b = -1 and c = 6

Putting the values of a, b and c in above formula, we have

x = (-(-1)±√(-1)²-4(3)(6) ) / 2(3)

x = (1±√1-72) / 6

x = (1±√-71) / 6

x = 1+√-71) / 6 and x = 1-√-71 / 6

Hence, the solutions are choices E and F.