Answer:
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.
Step-by-step explanation:
Here in this question, we want to state what will happen if the null hypothesis is true in a chi-square test.
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.
This is because at a higher level of discrepancies, there will be a strong evidence against the null. This means that it will be rare to find discrepancies if null was true.
In the question however, since the null is true, the discrepancies we will be expecting will thus be small and common.
Answer: 2a^2+22a+−1
Step-by-step explanation:
Let's simplify step-by-step.
2a^2−5a+(9)(3)a−1
=2a^2+−5a+27a+−1
Combine Like Terms:
=2a^2+−5a+27a+−1
=(2a^2)+(−5a+27a)+(−1)
=2a^2+22a+−1
Answer:
910 ft
Step-by-step explanation:
This question sets up the equation tan20°=x/2,500. Solve for X by multiplying 2,500 on both sides giving you x = 2,500tan20°. Finally, plug that in a calculator and you get 909.92. Round it to the nearest foot and you get 910
Answer:
B
Step-by-step explanation:
the more people who would've surveyed then the graph would be at the same rate.
