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Elodia [21]
3 years ago
11

Simplify the polynomial (2x^3 + x^2 - 4x) - (9x^3 + - 3x^2)

Mathematics
2 answers:
iragen [17]3 years ago
4 0
<span><span> (2x3-4x2-3x-9)/(x-3)</span> </span>Final result :<span> 2x2 + 2x + 3 </span>Step by step solution :<span>Step  1  :</span><span>Equation at the end of step  1  :</span><span> <span> Step  2  :</span></span><span>Equation at the end of step  2  :</span> <span>Step  3  :</span><span> 2x3 - 4x2 - 3x - 9 Simplify —————————————————— x - 3 </span>Checking for a perfect cube :

<span> 3.1 </span>  <span> 2x3 - 4x2 - 3x - 9</span>  is not a perfect cube 

Trying to factor by pulling out :

<span> 3.2 </span>     Factoring: <span> 2x3 - 4x2 - 3x - 9</span> 

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -3x - 9 
Group 2: <span> 2x3 - 4x2</span> 

Pull out from each group separately :

Group 1:   (x + 3) • (-3)
Group 2: <span>  (x - 2) • (2x2)</span>

<span>Bad news !! Factoring by pulling out fails : 

</span>The groups have no common factor and can not be added up to form a multiplication.

Polynomial Roots Calculator :

<span> 3.3 </span>   Find roots (zeroes) of :      <span> F(x) = 2x3 - 4x2 - 3x - 9</span>
Polynomial Roots Calculator is a set of methods aimed at finding values of  x  for which   F(x)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  x  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q  then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  2  and the Trailing Constant is <span> -9. 

 </span>The factor(s) are: 

of the Leading Coefficient : <span> 1,2 
 </span>of the Trailing Constant : <span> 1 ,3 ,9 

 </span>Let us test ....

<span><span>  P  Q  P/Q  F(P/Q)   Divisor</span><span>     -1     1      -1.00      -12.00   </span><span>     -1     2      -0.50      -8.75   </span><span>     -3     1      -3.00      -90.00   </span><span>     -3     2      -1.50      -20.25   </span><span>     -9     1      -9.00     -1764.00   </span><span>     -9     2      -4.50      -258.75   </span><span>     1     1      1.00      -14.00   </span><span>     1     2      0.50      -11.25   </span><span>     3     1      3.00      0.00   <span> x - 3 </span></span><span>     3     2      1.50      -15.75   </span><span>     9     1      9.00      1098.00   </span><span>     9     2      4.50      78.75   </span></span>


The Factor Theorem states that if <span>P/Q </span>is root of a polynomial then this polynomial can be divided by <span>q*x-p </span>Note that <span>q and p originate from P/Q </span>reduced to its lowest terms 

In our case this means that 
  <span> <span>2x3 - 4x2 - 3x - 9</span> </span>
can be divided with <span> x - 3 </span>

Polynomial Long Division :

<span> 3.4 </span>   Polynomial Long Division 
Dividing : <span> <span>2x3 - 4x2 - 3x - 9</span> 
                              ("Dividend")
</span>By         :   <span> x - 3    ("Divisor")
</span>

<span><span>dividend <span> 2x3 </span>-<span> 4x2 </span>- 3x - 9 </span><span>- divisor<span> <span>* 2x2</span> </span> <span> 2x3 </span>-<span> 6x2 </span>    </span><span>remainder   <span> 2x2 </span>- 3x - 9 </span><span>- divisor<span> <span>* 2x1</span> </span>   <span> 2x2 </span>- 6x   </span><span>remainder      3x - 9 </span><span>- divisor<span> <span>* 3x0</span> </span>      3x - 9 </span><span>remainder       0</span></span>

Quotient : <span> <span>2x2+2x+3</span>  </span>Remainder: <span> 0 </span>

Trying to factor by splitting the middle term

<span> 3.5 </span>    Factoring <span> 2x2+2x+3</span> 

The first term is, <span> <span>2x2</span> </span> its coefficient is <span> 2 </span>.
The middle term is, <span> +2x </span> its coefficient is <span> 2 </span>.
The last term, "the constant", is <span> +3 </span>

Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 2</span> • 3 = 6</span> 

Step-2 : Find two factors of  6  whose sum equals the coefficient of the middle term, which is  <span> 2 </span>.

<span><span>     -6   +   -1   =   -7</span><span>     -3   +   -2   =   -5</span><span>     -2   +   -3   =   -5</span><span>     -1   +   -6   =   -7</span><span>     1   +   6   =   7</span><span>     2   +   3   =   5</span><span>     3   +   2   =   5</span><span>     6   +   1   =   7</span></span>


Observation : No two such factors can be found !! 
Conclusion : Trinomial can not be factored

Canceling Out :

<span> 3.6 </span>   Cancel out <span> (x-3) </span> which appears on both sides of the fraction line.

Final result :<span> 2x2 + 2x + 3 </span><span>
</span>
Llana [10]3 years ago
3 0
The answer is 2x2 + 2x + 3
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3 years ago
An object is launched from a launching pad 144 ft. above the ground at a velocity of 128ft/sec. what is the maximum height reach
ollegr [7]

Answer:

18) a. h(x) = -16x² + vx + h(0) ⇒ h(x) = -16x² + 128x + 144

b. The maximum height = 400 feet

c. Attached graph

19) The rocket will reach the maximum height after 4 seconds

20) The rocket hits the ground after 9 seconds

Step-by-step explanation:

* Lets study the rule of motion for an object with constant acceleration

# The distance S = ut ± 1/2 at², where u is the initial velocity, t is the time

  and a is the acceleration of gravity

# The vertical distances h in x second is h(x) - h(0), where h(0)

   is the initial height of the object above the ground

∵ h(x) = vx + 1/2 ax², where h is the vrtical distance, v is the initial

  velocity, a is the acceleration of gravity (32 feet/second²) and x

  is the time

18)a.

∵ The value of a = -32 ft/sec² ⇒ negative because the direction

   of the motion

  is upward

∴ h(x) - h(0) = vx - (1/2)(32)(x²) ⇒ (1/2)(32) = 16

∴ h(x) = vx - 16x² + h(0)

∴ h(x) = -16x² + vx + h(0) ⇒ proved

* Find the height of the object after x seconds from the ground

∵ h(0) = 144 and v = 128 ft/sec

∴ h(x) = -16x² + 128x + 144

b.

* At the maximum height h'(x) = 0

∵ h'(x) = -32x + 128

∴ -32x + 128 = 0 ⇒ subtract 128 from both sides

∴ -32x = -128 ⇒ ÷ -32

∴ x = 4 seconds

- The time for the maximum height = 4 seconds

- Substitute this value of x in the equation of h(x)

∴ The maximum height = -16(4)² + 128(4) + 144 = 400 feet

c. Attached graph

19)

- The object will reach the maximum height after 4 seconds

20)

- When the rocket hits the ground h(x) = 0

∵ h(x) = -16x² + 128x + 144

∴ 0 = -16x² + 128x + 144 ⇒ divide the two sides by -16

∴ x² - 8x - 9 = 0 ⇒ use the factorization to find the value of x

∵ x² - 8x - 9 = 0

∴ (x - 9)( x + 1) = 0

∴ x - 9 = 0 OR x + 1 = 0

∴ x = 9 OR x = -1

- We will rejected -1 because there is no -ve value for the time

* The time for the object to hit the ground is 9 seconds

8 0
3 years ago
This one please. Thank you!!
lys-0071 [83]
I’m believe it’s the 3rd one but i’m not sure
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3 years ago
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