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3 years ago

11

Help!!! can someone help me solve this page im getting really confused I will mark you brainliest ☆ if you help me solve this :)

1 answer:

bearhunter [10]3 years ago

3 0

4 no. one i guess 10

not sure

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Find all the real values of X for which f(x)=0 <br><br> F(x)= x^3-x

Natalka [10]

Answer:

x=0,1,-1

Step-by-step explanation:

It factors as

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3 years ago

Simplify by dividing (-3/8) divided by 5/9

ElenaW [278]

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GuDViN [60]

Recall that

$\cot(u+v)=\dfrac{\cos(u+v)}{\sin(u+v)}=\dfrac{\cos u\cos v-\sin u\sin v}{\sin u\cos v+\cos u\sin v}=\dfrac{\cot u\cot v-1}{\cot v+\cot u}$

Also, recall that for all $\theta$ ,

$\cos^2\theta+\sin^2\theta=1$

With $\frac{3\pi}2$ , we can expect $\cos u>0$ , and with $0$ , $\sin v>0$ . So from the above identity it follows that

$\cos u=\sqrt{1-\sin^2u}=\dfrac45\implies\cot u=\dfrac{\cos u}{\sin u}=-\dfrac43$

and

$\sin v=\sqrt{1-\cos^2v}=\dfrac8{17}\implies\cot v=\dfrac{\cos v}{\sin v}=\dfrac{15}8$

and so

$\cot(u+v)=\dfrac{-\frac43\frac{15}8-1}{\frac{15}8-\frac43}=\boxed{-\dfrac{84}{13}}$

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3 years ago

PLZZ could someone help me out with this and explain

jenyasd209 [6]

Answer:

It would be D because X^2 is different from 3x you would just multiply X^2 by 1 and 3x by 1 to get x^2+3x

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1

Step-by-step explanation:

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